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omeli [17]
3 years ago
15

03. O preço a ser pago por uma corrida de táxi inclui uma parcela fixa, denominada bandeirada, e uma parcela que depende da dist

ância percorrida. Se a bandeirada custa R$ 3,20 e cada quilômetro rodado custa R$ 1,50, qual o valor de v a pagar em uma corrida de n quilômetro? * 1 ponto a) v = 1,50 + 3,20n b) v = 3,20.N c) v = 3,20.N - 1,50 d) v = 3,20 + 1,50n e) v = 1,50n
Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer: d) v = 3.20 + 1.50n.

Step-by-step explanation:

Let 'v' be the price to pay in a 'n' kilometer.

Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.

Flag costs = $ 3.20 and

Each kilometre run costs = $ 1.50

Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs +   (n)× (Each kilometre run costs )

⇒ v= 3.20 + 1.50n

Hence, the correct option is  d) v = 3.20 + 1.50n.

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<h3><u>The x intercept is at (-7, 0).</u></h3><h3><u>The y intercept is at (0, 1).</u></h3>

To find both the x and the y intercept, we need to solve one at a time.

For the x intercept, we need to make the value of y equal to 0, and solve for x.

-x + 7y = 7

-x + 7(0) = 7

-x = 7

Multiply both sides by -1.

x = -7

The x intercept is -7.


Now for the y intercept.

-(0) + 7y = 7

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Divide both sides by 1.

y = 1

The y intercept is at 0, 1.

5 0
3 years ago
Alex bought four 15-pound bags of dog food, three 4 1/2 pound bags of cat food, and two 1/2-pound bags of fish food. How many po
garri49 [273]

Answer:

15+4.5+0.5=20

Alex bought 20 pounds of pet food

Step-by-step explanation:

Hope this helps!!

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6 0
3 years ago
0.25(8)+0.15x=0.35(20+x)
IRINA_888 [86]
X=-25 is the answer.
3 0
3 years ago
You are comparing prices from 2 office supply stores. Your office needs 5 cases of blue paper. Home &amp; Office Headquarters li
melomori [17]


5x[$25.85-($25.85 x 0.10) ] + (5 x 2.50)=$128.83 compared to[ 5 x 27.36( $27.36 x 0.15)]+ 10.00= 126.28 is the least amount.

answer is ------> $126.28

8 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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