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omeli [17]
3 years ago
15

03. O preço a ser pago por uma corrida de táxi inclui uma parcela fixa, denominada bandeirada, e uma parcela que depende da dist

ância percorrida. Se a bandeirada custa R$ 3,20 e cada quilômetro rodado custa R$ 1,50, qual o valor de v a pagar em uma corrida de n quilômetro? * 1 ponto a) v = 1,50 + 3,20n b) v = 3,20.N c) v = 3,20.N - 1,50 d) v = 3,20 + 1,50n e) v = 1,50n
Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer: d) v = 3.20 + 1.50n.

Step-by-step explanation:

Let 'v' be the price to pay in a 'n' kilometer.

Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.

Flag costs = $ 3.20 and

Each kilometre run costs = $ 1.50

Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs +   (n)× (Each kilometre run costs )

⇒ v= 3.20 + 1.50n

Hence, the correct option is  d) v = 3.20 + 1.50n.

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Graph the line whose y-intercept is - 9 and whose x-intercept is 5.
Nostrana [21]

Answer:

y=1.8x-9

Step-by-step explanation:

if they are intercepts so the x/y will be zero, so in y intetceot the x is zero, and in the x itercept the y is zero.

0,-9

5,0

we calculate the slooe / rise

-9-0/0-5 = 1.8

we then use this formula

y-y1=rise(x-x1)

y-0=1.8(x-5)

y=1.8x-9

4 0
3 years ago
Your schools talent show will feature 12 solo acts and ensemble 2 acts. The show will last 90 min. The 6 solo performers judged
kicyunya [14]
A.  12*x + 2*y = 90
       6*x + 2*y = 60

To write system of equation you just need to sum all solo and ensemble acts and make it equal to how much they will last for.

B.  Here we can multiply second equation with negative 1 and add it to first equation.
6x = 30
x = 5

now we replace x in any of 2 equations to get y.
30+2y = 60
2y = 30
y=15

Solo acts are 5 minutes long and ensemble acts are 15 minutes long
3 0
3 years ago
The league championship 800 meter race has 6 runners.
s2008m [1.1K]

Answer: 120

Step-by-step explanation:

Given : The league championship 800 meter race has 6 runners.

The number of positions = 3

Since order matters here , so we use Permutation.

The permutation of n things taking r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of different ways they place first, second, and third :_

^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6\times5\times4\times3!}{3!}=120

Hence, they can place first, second, and third in 120 different ways .

7 0
3 years ago
10 points to whoever answers this CORRECTLY and QUICKLY. Thanks
Ainat [17]
1 solution 

x = -1/2

-------------------------------------
4 0
3 years ago
Five to the power of five (16 power of 2 times 5 to the power of 3)power 3
11Alexandr11 [23.1K]

Answer:

1.024x10^17

Step-by-step explanation:

5^5(16^2x5^3)^3

find the 5^5

3125(16^2x5^3)^3

distribute the power of 3 into the parentheses

3125(16^6x5^9)

multiply

3125(16777216x1953125)

1.024x10^17

8 0
2 years ago
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