A rectangle with sides 15 and w has perimeter
We want this quantity to be at most 50, so it must be less than or equal to 50:
For the record, this implies that
So, the width can be at most 10.
Its is 74 because you add all of them then subtract it from the total which in your case is 360
X = first venture, y = second venture, z = third venture
x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....
x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000
x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000
2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000
x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000
first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
Linear combination method just means to add the equations so that one variable with cancel. In this case the a values are already set up so that they will cancel.
2a + 3b = 1
-2a + b = 11
4b = 12
b = 3
now put 3 back into either of the original equations and solve for a.
2a + 3(3) = 1
2a + 9 = 1
2a = -8
a = -4
(-4,3)
Answer:
468
Step-by-step explanation:
=13[42-6]
=13 (36)
=13×36
=468
