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Tanzania [10]
3 years ago
5

Pepper Jackie is making posters with a map of the area around the youth center the map she has is too small for the poster so sh

e wants to make it 3 times bigger if the current scale of the map is 1 inch to 12 yards what will be the scale for the new map
Mathematics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

1:4

Step-by-step explanation:

Current map scale 1:12

Three times bigger would be

3\times \frac{1}{12}=\frac{1}{4}=1:4

This would mean that 1 inch on the map would be 4 yards in the real world

Let us take example

If something measured 100 yards in the real world then in the old map it would be \frac{100}{12}=8.33 inches in the map

Now in the new map if something measured 100 yards in the real world then in the new map it would be  \frac{100}{4}=25 inches.

So, the new scale would be 1:4, this means that 1 yard in the actual world would be 4 inches in the map.

Katarina [22]3 years ago
5 0
4inches and 4yards that is what I got but it might be wrong
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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
What is the name of the property given below ? If ab = 0 then a = 0 , b = 0 or both a = 0 and b = 0 . A. Zero property B. Distri
FromTheMoon [43]

Answer:

c. zero product rule

Step-by-step explanation:

apex

3 0
3 years ago
36 singers in the choir 5/6 are boys how many of the singers are girls
Aleksandr [31]

Answer:

6

Step-by-step explanation:

5/6 of 30 = ?

5            x

----    =   ----

6             36

36 x 5 = 180

180/6 = 30

That means 30 singers are boys.

36 - 30 = 6 (the number of girls)

5 0
3 years ago
Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Josiah has punch c
love history [14]

Let x be the number of weeks; therefore, the two linear equations are

\begin{gathered} T=2+7x \\ \text{and} \\ C=11+4x \end{gathered}

Where T stands for the punches on the tea punch card and C for the punches on the coffee punch card.

Solving by substitution. Set T=C, then

\begin{gathered} T=C \\ \Rightarrow2+7x=11+4x \\ \Rightarrow3x=9 \\ \Rightarrow x=\frac{9}{3}=3 \\ \Rightarrow x=3 \end{gathered}

Thus, substitute the value of x=3 into the first equation,

\begin{gathered} x=3 \\ \Rightarrow T=2+7\cdot3=23 \\ \Rightarrow T=23 \end{gathered}

Thus, after 3 weeks, Josiah will have the same number of punches on each card, and he will have 23 punches on each card.

6 0
1 year ago
Product of 2 numbers increased by 9
tino4ka555 [31]
(X * y) + 9
Xy + 9
you can't reduce it further

~Zoe
4 0
3 years ago
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