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3 years ago

in 25 minutes Li can run 10 laps around the track. consider the number of laps she can run per minute

Mathematics

2 answers:

Tresset [83]3 years ago

8 0

She can run 2.5 miles a minute

strojnjashka [21]3 years ago

7 0

Here you are going from 25 minutes to 1 minute; essentially, if you look at this algebraiclly you have 25 min=10 laps to 10 minutes= x laps; set up a proportion for this to get: 25 min/10 laps =1minutes/ x laps Solving by cross multiplying; multiply the denominator to the opposite numerator (this makes more sense when writing as a fraction; you will multiply in an "x" shape) then solve as the algebra problem of 25=10x ; divide both sides by 10 to isolate x and this will give you the answer of x=2.5

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Simplify each expression. (7x+x^4+x^3)-(6x-2x^3+8x^4)

aleksandrvk [35]

the answer is x + 3x^3 - 7x^4

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3 years ago

Order the rational numbers from least to greatest. -3/4. -0.85. 0.55. 1/4. -0.9. -1/2

trasher [3.6K]

Answer:

-0.9, -0.85, -3/4, -1/2, 1/4, 0.55

Step-by-step explanation:

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3 years ago

Read 2 more answers

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

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I think Hannah is right

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3 years ago

WILL GIVE BRAINIEST Which of the following is NOT a perfect square? Question 3 options: 36 25 49 81 35 144 100

jok3333 [9.3K]

Answer:

Step-by-step explanation:

The way I know is because I memorized every square up to 33.

BUT that's probably not helpful to you.

Remember that every perfect square has an odd number of factors. I'm not going to list them all out, but the factors of 35 are 1, 5, 7, and 35, giving it an even number of factors. All the rest have an odd number of factors because of the property of a perfect square: a number times itself gives a perfect square, but that number only counts as 1 factor.

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3 years ago