Answer:
The transverse component of acceleration is 26.32 where as radial the component of acceleration is 8.77
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s
So the transverse component of acceleration are given as
Here
So
The transverse component of acceleration is 26.32
The radial component is given as
Here
So
The radial component of acceleration is 8.77
Answer:
t = 12,105.96 sec
Explanation:
Given data:
weight of spacecraft is 2000 kg
circular orbit distance to saturn = 180 km
specific impulse = 300 sec
saturn orbit around the sun R_2 = 1.43 *10^9 km
earth orbit around the sun R_1= 149.6 * 10^ 6 km
time required for the mission is given as t
where
is gravitational parameter of sun = 1.32712 x 10^20 m^3 s^2.
t = 12,105.96 sec
The speed of the spaceship relative to the galaxy is 0.99999995c.
A light-year measures distance rather than time (as the name might imply). A light-year is a distance a light beam travels in one year on Earth, which is roughly 6 trillion miles (9.7 trillion kilometers). One light-year equals 5,878,625,370,000 miles. Light moves at a speed of 670,616,629 mph (1,079,252,849 km/h) in a vacuum.We multiply this speed by the number of hours in a year to calculate the distance of a light-year (8,766).
The Milky way galaxy is 100,000 light years in diameter.
The galaxy's diameter is a mere 1. 0 ly.
We know that ;
L = 1 light year
L₀ = 100,000 light year
Therefore, the speed of the spaceship relative to the galaxy is 0.99999995c.
Learn more about a light year here:
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