2 years ago

Measurement conversions [metric to metric] 568 cm = m

Physics

1 answer:

Trava [24]2 years ago

7 0

Answer:

5.68 meters

Explanation:

hope this helps!

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A train moves uniform velocity of 36km/h for 15 sec.find distance

vesna_86 [32]

Answer:

S = V × t

Explanation:

first convert 36km/h to m/s

36km/h=36*5/18=180/18=10m/s

d =s*t

=10*10=100m

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John flies directly east for 20km, then turns to the north and flies for another 10 km before dodging a flock of geese. what’s t

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The distance is 30 km and the displacement is 22.4 km North East

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A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a

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2 years ago

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Tammy leaves the office, drives 34 km due north, then turns onto a second highway and continues in a direction of 35◦ north of e

Natasha2012 [34]

Answer:

The total displacement is 102 km $51^o$ north of east.

Explanation:

We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.

$d_n=34km+79km*sin(35^o)=79km$

and

$d_e=79*cos(35^o)=65km$

The total displacement is given by:

$D=\sqrt{(79km)^2+(65km)^2}=102km$

with an agle of:

$\alpha =arctg(\frac{79km}{65km})=51^o$

4 0

2 years ago

A uniform 2.50m ladder of mass 7.30kg is leaning against a vertical wall while making an angle of 51.0degree with the floor. A w

Zigmanuir [339]

Answer:

19.95 J

Explanation:

The center of mass of the ladder is initially at a height of:

$h_1=\frac{L}{2}sin\theta$

The center of mass of the ladder ends at a height of:

$h_2= \frac{L}{2}sin90$ =L/2

So, the work done is equal to the change in potential energy which is:

W = PE = $mg(h_2-h_1)$

now $h_2-h_1= 1-sin\theta$

therefore

W = [mgL/2]×[1 - sin(theta)]

W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]

solving this we get

W = 19.95 J

8 0

2 years ago

Measurement conversions [metric to metric] 568 cm = m​

Measurement conversions [metric to metric] 568 cm = m