if the mean is 70 minutes, then 90 minutes is 2 standard deviations above 70. if you look at the bell curve i drew, the percent of exams that took over 90 minutes is 2.5% <span>
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7 0

3 years ago

Read 2 more answers

Find the length AB round your answer to the tenth

Kobotan [32]

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$AB = \sqrt{ ({3 - ( - 2)})^{2} + ({4 - 0})^{2} } \\$

$AB = \sqrt{ ({3 + 2})^{2} + {4}^{2} }$

$AB = \sqrt{ {5}^{2} + {4}^{2} }$

$AB = \sqrt{25 + 16}$

$AB = \sqrt{41}$

$AB = 6.403$

$AB = 6.4$

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3 0

3 years ago

Point J (-4, -6) and point K (4, 4) are located on a coordinate grid. Which measurement is closest to the distance between point

shepuryov [24]

Answer:

The points are sqrt(164) or 2sqrt(41) units apart.

Explanation:

You didn't provide the options in your question. But to find the distance, you need to use the distance formula.

d=sqrt((y2-y1)^2 + (x2-x1)^2)

d is the distance, and (x1, y1) and (x2, y2) are the points.

Use point J (-4,-6) for (x1,y1) and point K (4,4) for (x2, y2).

d=sqrt((4-(-6))^2 + (4-(-4))^2)

=sqrt(10^2 + 8^2)

=sqrt(100+64)

=sqrt(164)=2sqrt(41)

You can compare this to the answer options and find the closest. Hope I could help! :)

3 0

3 years ago