Answer:
According to the given problems the one that gets closer is the first option. ^12sqrt27/2
Step-by-step explanation:
<em>Simplify the radical by breaking the radicand up into a product of known factors.</em>
The answer for the first question is 12
√
27
/ 2
Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
H (4.84) will be the correct answer
Answer: 1/5
Step-by-step explanation:
Answer:
a.
-6a²/ b
b.
5y³
Step-by-step explanation:
a
-6a²b⁻¹
-6a²/ b
b.
5/ y⁻³
5 / 1/ y³
5 * y³/1
5y³
