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Y_Kistochka [10]
3 years ago
15

Find the area of the shaded region where s 18. Round your answer to two decimal places.​

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

17.3&

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Sarah have 40 nickels in her bank her dad gave her 44 more nickels how many nickels does Sarah have now ​
Evgen [1.6K]

Answer:

She now has 84 nickles. :)

Step-by-step explanation:

40+44=84

3 0
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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
3 years ago
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THE PROOF IS IN YOUR BIBLE

Step-by-step explanation:

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First you add250+250 then you add 9+9 or you could do250×9 2 times then add them together . never mind just do 250×9 2times and that will eqaul 2,250 then add 2250+ 2250and you got the answer and the answer is 4500
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3 years ago
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A ladder leaning against a wall forms a triangle and exterior angles with the wall and the ground. What are the measures of the
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11x° is interior angle of ladder to the ground
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