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3 years ago

The average person drinks one pint of milk a day. At this rate, how many gallons will a person drink in a leap year.

1 answer:

3 0

Leap years have 366 days, and there are 8 pints per gallon. So we divide the 366 days by the 8 pints per 1 gallon. We end up getting:
45.75 gallons in 1 leap year.

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Why did the feudal system rely on a high degree of local independence?

kobusy [5.1K]

Answer:Feudalism helped protect communities from the violence and warfare that broke out after the fall of Rome and the collapse of strong central government in Western Europe. Feudalism secured Western Europe's society and kept out powerful invaders. Feudalism helped restore trade. Lords repaired bridges and roads.

Step-by-step explanation:

6 0

3 years ago

A mixture of acid and water is 35% acid if the mixture contains a total of 40 liters how many liters of pure acid are in the mix

melamori03 [73]

40/10 = 4 x 3.5 = 16 litres
16/2 = 8
Therefore 8 litres of pure water and 8 kites of pure acid

7 0

3 years ago

The radius of a spherical balloon is 4.5 inches.

Natalka [10]

Answer:

The volume of the balloon is 18.84 inches³

Step-by-step explanation:

* Lets talk about the sphere

- Its a solid

- It has surface area = 4πr²

- It has no lateral area

- It has no faces

- It has no vertices

- It has no edges

- Its volume = (4/3) π r³

* In our problem the balloon shaped a sphere

- Its radius = 4.5 inches

- The value of π = 3.14

* Lets calculate its volume

∵ The radius = 4.5 inches

∵ π = 3.14

∵ The volume = (4/3) π r³

* Substitute the values of r and π in the formula

∴ The volume = (4/3) × 3.14 × 4.5 = 18.84 inches³

* The volume of the balloon is 18.84 inches³

4 0

3 years ago

Read 2 more answers

F over 6 minus 1.2 equals -30

ch4aika [34]

For (f/6) - 1.2 = -30, the answer is f = -172.8
for f/(6-1.2) = -30, the answer is f = -144

7 0

3 years ago

The volume of a spherical balloon is increasing at the constant rate of 8 cubic feet per minute. How fast is the radius incresin

OverLord2011 [107]

Answer:

Rate of increase of radius = 0.0064 ft/sec

Rate of increase of surface area = 1.61 $ft^2/sec$

Step-by-step explanation:

Given that:

Rate of change of volume of a spherical balloon = 8 cubic feet per minute

$\dfrac{dV}{dt} = 8 ft^3/min$

Radius, $r$ = 10 feet

To find:

The rate of change of radius at this moment and rate of change of surface area at this moment?

Solution:

First of all, let us have a look at the formula:

$1.\ V = \dfrac{4}{3}\pi r^3\\2.\ A =4\pi r^2$

Now, differentiating the volume and area, we get:

$\dfrac{dV}{dt} = \dfrac{4}{3}\times 3 \pi r^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dV}{dt} = 4 \pi r^2 \dfrac{dr}{dt}$

$\dfrac{dA}{dt} = 4\pi \times 2 r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\pi r \dfrac{dr}{dt}$

$\dfrac{dV}{dt} = 8 = 4\pi r^2 \dfrac{dr}{dt}\\\Rightarrow 8 = 4\times 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow 2 = 3.14 \times 10^2 \dfrac{dr}{dt}\\\Rightarrow \dfrac{dr}{dt} = 0.0064\ ft/sec$

$\dfrac{dA}{dt} = 8\times \pi \times r \dfrac{dr}{dt}\\\Rightarrow \dfrac{dA}{dt} = 8\times 3.14 \times 10 \times 0.0064\\\Rightarrow \dfrac{dA}{dt} = \bold{1.61 \ ft^2/sec}$

7 0

3 years ago