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GarryVolchara [31]
3 years ago
12

solve the system of equations 3y 2z = 12 and y – z = 9. a. y = 24, z = 15 b. y = 6, z = 15 c. y = 6, z = –3 d. y = –6, z = 15

Mathematics
1 answer:
Alex73 [517]3 years ago
7 0
If you would like to solve the system of equations 3y + 2z = 12 and y - z = 9, you can do this using the following steps:

<span>3y + 2z = 12
y - z = 9 ... y = 9 + z
</span>___________
<span>3y + 2z = 12
</span>3 * (9 + z) + 2z = 12
27 + 3z + 2z = 12
5z = 12 - 27
5z = -15
z = -15/5
z = -3

<span>y = 9 + z = 9 - 3 = 6
</span>
The correct result would be <span>c. y = 6, z = –3.</span>
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2.1 , - 6/10 , -9/4 , -0.75 , 5/3 , least to greatest
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Answer:

-9/4, -0.75, -6/10, 5/3, 2.1

Step-by-step explanation:

This is a lot easier to figure out if you simplify the fractions and then change them to decimals

So -9/4 = -2 1/4 or -2.25

-0.75

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The next one would be -0.75, because it is the second biggest negative fraction.

The next one is -0.60 because that is the 3rd biggest negative fraction (or the smallest because this is the last negative)

Now, because we're in the positives we start with 1.67, because it is smaller than the other number.

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