solve the system of equations 3y 2z = 12 and y – z = 9. a. y = 24, z = 15 b. y = 6, z = 15 c. y = 6, z = –3 d. y = –6, z = 15
1 answer:
If you would like to solve the system of equations 3y + 2z = 12 and y - z = 9, you can do this using the following steps:
<span>3y + 2z = 12
y - z = 9 ... y = 9 + z
</span>___________
<span>3y + 2z = 12
</span>3 * (9 + z) + 2z = 12
27 + 3z + 2z = 12
5z = 12 - 27
5z = -15
z = -15/5
z = -3
<span>y = 9 + z = 9 - 3 = 6
</span>
The correct result would be <span>c. y = 6, z = –3.</span>
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