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Lynna [10]
3 years ago
15

A standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was 14901490 and the standard dev

iation was 320320. The test scores of four students selected at random are 19001900​, 12401240​, 21902190​, and 13701370. Find the​ z-scores that correspond to each value and determine whether any of the values are unusual.
Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
<h2>Answer with explanation:</h2>

Given : A standardized​ exam's scores are normally distributed.

Mean test score : \mu=1490

Standard deviation : \sigma=320

Let x be the random variable that represents the scores of students .

z-score : z=\dfrac{x-\mu}{\sigma}

We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .

For x= 1900

z=\dfrac{1900-1490}{320}\approx1.28

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 1240

z=\dfrac{1240-1490}{320}\approx-0.78

Since it lies between -1.96 and 1.96 , thus it is not unusual.

For x= 2190

z=\dfrac{2190-1490}{320}\approx2.19

Since it is greater than 1.96 , thus it is unusual.

For x= 1240

z=\dfrac{1370-1490}{320}\approx-0.38

Since it lies between -1.96 and 1.96 , thus it is not unusual.

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Step-by-step explanation:

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Combine like terms:

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3 years ago
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Rate how emo I am!!!
Nutka1998 [239]
5 ish not really emo
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2 years ago
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20 POINTS
SIZIF [17.4K]
Let get all the information.
Mean:394
Deviation:35
Looking for At Least 380 feet
To find the z score you take the wanted probality subtract the mean and divide by the deviation.
z=(380-394)/35.
z=-0.4
So far so good.
But when he looked at the table he looked at probability that the home runs are less then 380 feet.
From this table
http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf
To find the answer you have to take 1-(the probability that the home runs are less than 380 feet)or 1-0.3446=0.6554
He made an error in his calculation.
8 0
3 years ago
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