Answer:
Step-by-step explanation:
It would be more obvious if it says z is a standard Normal variable and that the question is related to statistics.
From "Computing Probabilities Using the Cumulative Table" , the probability of z is less than 1.16, P(z<1.16) = 0.8770.
The expected value of the first game is -$0.50 and of the second game is -$0.52.
There are 10³ possible numbers for the lottery, and only 1 of them will match in the correct order; this gives a probability of 1/1000. To find the expected value, we multiply this by the winnings (499 after the $1 cost); we also multiply the probability of losing (999/1000) by the amount lost (-1):
1/1000(499)+999/1000(-1)
499/1000 - 999/1000 = -500/1000 = -0.50
For the second game, since the number is "boxed", there are 3! ways to get the correct digits; this gives a probability of 6/1000. Multiply this by the winnings, 79 (after the $1 cost); multiply the probability of losing (994/1000) by the loss (-1):
6/1000(79) + 994/1000(-1) = 474/1000 - 994/1000 = -520/1000= -0.52
Answer:
4500
Step-by-step explanation:
you just need to see where the line stops at the price and drag your finger across to see how many people :}
Answer:
A, B, and C
Step-by-step explanation:
a). -6 ÷ 2 x 5 1/3
= -3 x 5 1/3
= -16
b). 24 ÷ (-3) + 1/2
= -8 + 1/2
= -7.5
c). 36 ÷ 4 x (-2)
= 9 x -2
= -18
d). -54 ÷ (-9) x (-3 2/3)
6 x -3 2/3
= -22
Answer:
3/8
Step-by-step explanation: