Given:
The bases of a trapezoid lie on the lines
![y=2x+7](https://tex.z-dn.net/?f=y%3D2x%2B7)
![y=2x-5](https://tex.z-dn.net/?f=y%3D2x-5)
To find:
The equation that contains the midsegment of the trapezoid.
Solution:
The slope intercept form of a line is
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Where, m is slope and b is y-intercept.
On comparing
with slope intercept form, we get
![m_1=2,b_1=7](https://tex.z-dn.net/?f=m_1%3D2%2Cb_1%3D7)
On comparing
with slope intercept form, we get
![m_2=2,b_2=-5](https://tex.z-dn.net/?f=m_2%3D2%2Cb_2%3D-5)
The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.
![m=m_1=m_2=2](https://tex.z-dn.net/?f=m%3Dm_1%3Dm_2%3D2)
The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.
![b=\dfrac{b_1+b_2}{2}](https://tex.z-dn.net/?f=b%3D%5Cdfrac%7Bb_1%2Bb_2%7D%7B2%7D)
![b=\dfrac{7-5}{2}](https://tex.z-dn.net/?f=b%3D%5Cdfrac%7B7-5%7D%7B2%7D)
![b=\dfrac{2}{2}](https://tex.z-dn.net/?f=b%3D%5Cdfrac%7B2%7D%7B2%7D)
![b=1](https://tex.z-dn.net/?f=b%3D1)
So, the y-intercept of the required line is 1.
Putting m=2 and b=1 in slope intercept form, we get
![y=2x+1](https://tex.z-dn.net/?f=y%3D2x%2B1)
Therefore, the equation of line that contains the midsegment of the trapezoid is
.