Question

Enter the equation of the circle described below. Center (5, 2), radius = 3

Answer 1

For a circle with center (h,k) and radius, r
the equaiton is
$(x-h)^2+(y-k)^2=r^2$

so

center=(5,2), radius=3

$(x-5)^2+(y-2)^2=3^2$
$(x-5)^2+(y-2)^2=9$

Answer 2

Equation of the circle;
$(x-a)^{2} + (y-b)^{2} = r^{2}$
a=5, b=2 and r= 3
$(x-5)^{2} + (y-2)^{2} = 3^{2}$