Answer:
P(not3)=5/6=.83
Step-by-step explanation:
Find probability of a die that didn’t have a 3 means that it could have a 1,2,4,5,6. This is 5out of 6.
5/6=.83
First you multiply 3 x 1000 which is 3,000. Then you too 2 x 100 which is 200. Lastly you subtract 3000 from 200 and you get 2800.

Differentiate both sides, treating
as a function of
. Let's take it one term at a time.
Power, product and chain rules:



Product and chain rules:




Product and chain rules:




The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

Isolate the derivative, and solve for it:


(See comment below; all the 6s should be 2s)
We can simplify this a bit by multiplying the numerator and denominator by
to get rid of that fraction in the denominator.

Answer:

Step-by-step explanation:
STEP 1:
2/3 + 7/10 = ?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(2/3, 7/10) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
*
+
= ?
Complete the multiplication and the equation becomes

The two fractions now have like denominators so you can add the numerators.
Then:

This fraction cannot be reduced.
The fraction 41/30
is the same as
41 divided by 30
Convert to a mixed number using
long division for 41 ÷ 30 = 1R11, so
41/30 = 1 11/30
Therefore:
2/3+7/10= 1 11/30
STEP 2:
41/30 + -2/3
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(41/30, -2/3) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

The two fractions now have like denominators so you can add the numerators.
Then:

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using
GCF(21,30) = 3

Therefore:
|
Volume of sphere = 4/3 x pi x r^3
Volume of large sphere:
4/3 x 3.14 x 14^3 = 11488.21 cubic cm
Volume of smaller sphere:
4/3 x 3.14 x 2^3 = 33.49 cubic cm
Number of small spheres = volume of large sphere/ volume of small sphere
11488.21 / 33.49 = 343.03
Round to 343 small spheres