See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35
minus original aera
which is 5 by 7 which is 35
4a²+24a+35-35=4a²+24a
3rd option I think, can't tell which is which
I reduced the equation to a - 6 (2/3)
Answer:
<h2>a=V⅓=1728⅓≈12</h2><h2 />
Step-by-step explanation:
<h2>Using the formula</h2><h2>V=a3</h2>
<h2>it is right answer </h2><h3>hope it will help you </h3>
Using proportions, the coordinates of the point 3/4 of the way from P to Q are: (0,4).
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
We want to find the coordinates of point M(x,y) 3/4 of the way from P to Q, hence the rule is given by:
M - P = 3/4(Q - P)
For the x-coordinate, we have that:
x + 6 = 3/4(2 + 6)
x + 6 = 6
x = 0.
For the y-coordinate, we have that:
y + 5 = 3/4(7 + 5)
y + 5 = 9.
y = 4.
The coordinates are (0,4).
More can be learned about proportions at brainly.com/question/24372153
#SPJ1
Answer:
Step-by-step explanation:
We want to find the Riemann sum for 
with n = 6, using left endpoints.
The Left Riemann Sum uses the left endpoints of a sub-interval:
where 
.
Step 1: Find 
We have that 
Therefore, 
Step 2: Divide the interval ![\left[0,\frac{3 \pi}{4}\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cfrac%7B3%20%5Cpi%7D%7B4%7D%5Cright%5D)
into n = 6 sub-intervals of length 
![a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b](https://tex.z-dn.net/?f=a%3D%5Cleft%5B0%2C%20%5Cfrac%7B%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B4%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B4%7D%5Cright%5D%3Db)
Step 3: Evaluate the function at the left endpoints
Step 4: Apply the Left Riemann Sum formula
