Answer:
Option A.) 20 pounds of walnuts and 25 pounds of almonds is correct.
Step-by-step explanation:
i) let x be the the number of pounds of almonds
ii) let y be the number of pounds of walnuts
iii) therefore x + y = 45 pounds of the mixture
iv) 1.2x + 0.75y = 1.00 
45 = 45
v) Multipling equation in iv) by 4 we get
4.8x + 3y = 180
vi) multiplying equation in iii) by 3 we get
3x + 3y = 135
vii) subtracting equation vi) from equation v) we get 1.8x = 45
ix) therefore we get x = 45/1.8 = 25 pounds of almonds
x) therefore 25 + y = 45 .... substituting value of x from ix) in iii) we get
therefore y = 20 pounds of walnuts
Therefore option A.) 20 pounds of walnuts and 25 pounds of almonds is correct.
Answer:
Option b is correct.
Step-by-step explanation:
From the given condition : Seven less than the quotient of a number, x, and twelve is five times the number.
Here, the number is x
The quotient of a number x and twelve is expressed as , 
Seven less than the quotient of a number, x, and twelve is expressed as, 
Five times the number mean, 
Therefore, we have an equation in the form of <em>x</em> from the given condition as:
.
Answer: 5 times 5 plus 11 plus 11
Step-by-step explanation:
Creating an algebra problem that equals to 47.
5 times 5 is 25
25 plus 11 is 36
36 plus 11 is 47
Answer:
122*
122 degrees
Step-by-step explanation:
m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*
Solution:
As per given data,
m∠GEF = 5m∠DEG - 13* … (i)
m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)
Substituting value of m∠GEF in (ii)
We get,
(5m ∠DEG - 13*) + m∠DEG = 149*
6m ∠DEG - 13* = 149*
6m ∠DEG = 149* + 13* = 162*
m∠DEG = * = 27*
Substituting value of m∠DEG in (i)
We get,
m∠GEF = 5(27*) - 13*
m∠GEF = 135* - 13* = 122*
Answer:
Hi Sophia! The answer is the option 3!
Step-by-step explanation:
Check the picture!
