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ser-zykov [4K]
4 years ago
15

Find the x- and y- intercepts Of 6=x-3y

Mathematics
1 answer:
nordsb [41]4 years ago
4 0

x intercept is 6,0

y intercept is 0, -2

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Help!!! evaluate peicewise functions
aksik [14]

Answer:

9

Step-by-step explanation:

You choose the middle one because 3<(4)<10 makes sense where as the other ones don't when you plug in 4. Then you solve the equation which is x^2-7 and then you get 16-7 which is 9.

4 0
2 years ago
The percent of licensed U.S. drivers (from a recent year) that are female is 48.60. Of the females, 5.03% are age 19 and under;
docker41 [41]

Answer:

a) 51.4

b) answer attached

c) 48.59% female

Step-by-step explanation:

a) Male driver = 100-48.6 = 51.4%

b) answer attached below

c) probability that out of 20-64 group a randomly selected sample is female

( 39.54 ÷ 81.36 ) x 100

= 48.59% chance of her being a female

Download docx
6 0
3 years ago
At the market 5 light bulbs cost 9.85. How much do 7 light bulbs cost?
Leya [2.2K]
The unit rate is $1.97 per lightbulb. Multiply $1.97 by 7 to get 13.79
5 0
3 years ago
Read 2 more answers
(x+3)^2+5=-28
Sidana [21]

Answer:

Description

Step-by-step explanation:

a. 2 solutions

b. 2 imaginary solutions

c. If the discriminant is positive, then it will have 2 real solutions as the square root of a positive number always equals a positive number. If the discriminant is negative, the quadratic equation will have 2 imaginary solutions, as the square root of a negative number is always imaginary. If the discriminant equals 0, it will have only 1 real solution.

3 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
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