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4 years ago

44 Given the balanced ionic equation:

1 answer:

6 0

To solve this redox equation, we divide the equation into two parts: the oxidation and the reduction part. The reduction part is 3 Pb 2+ = 3 Pb while the oxidation part is 2 Cr = 2 Cr3+. We balance the charges. 3 Pb 2+ + 6e- = 2 Pb and 2 Cr = 2 Cr 3+ + 6e-. Adding the two equations, the 6 e- just cancels out. Hence for 3 moles of lead ions, there are 6 moles of electrons gained.

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Name the alcohol that contains five carbons and has a hydroxyl (alcohol) group on the second carbon.

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Pentanol contains five carbons and has a hydroxyl group on the second carbon. (C5H11OH)

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4 years ago

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3 years ago

Read 2 more answers

A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution

alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

Explanation:

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $$\frac{mass}{molar mass}$

= $$\frac{318.6 g}{342.3 g/mol}$

= 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $$\frac{mass}{density}$

= $$\frac{4905 g }{1000 g/L}$

= 4.905 L

Now we can find the molarity = $$\frac{moles}{Volume(L)}$

= $$\frac{0.93 moles}{4.905 L}$

= 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}$

= 1200 g

Now we have to find out the amount of HCl in grams as,

$$\frac{1200g \times 39 g HCl }{100 g solution}$

= 468 g HCl

Now we have to find the number of moles,

moles = $$\frac{468 g}{36.46 g/mol}$

= 12.8 moles

Molarity of HCl = $$\frac{12.8 moles}{1 L }$

= 12.8 M

So the molarity of HCl is 12.8 M.

6 0

3 years ago

Given that blood exerts the same osmotic pressure as a 0.15 M NaCl solution, which solution could be the hypertonic solution?/se

inna [77]

Answer:

a. 0.68 M NaCl solution

Explanation:

The tonicity of a solution can either be hypotonic, hypertonic and isotonic. Hypertonic solution is a solution which possesses a higher concentration of solute in relation to another solution.

According to this question, a solution is said to contain 0.15 M NaCl solute. This means that a solution that will be hypertonic to this solution will have a much more concentration of solute, which based on the options provided is the 0.68 M NaCl solution.

5 0

3 years ago

The density Aluminum is 2.7g/cm3. What is the mass if the volume is 21 cm

marissa [1.9K]

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mass = density x volume

Substitute your values in

mass = 2.7 x 21

Solve:

mass = 56.7g

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6 0

3 years ago