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r-ruslan [8.4K]
3 years ago
11

What mass of iron is needed to react with sulfur in order to produce 96 grams of iron (|||) sulfide according to the following e

quation?
2Fe+3S—>Fe2S3
Chemistry
1 answer:
Stells [14]3 years ago
3 0

Answer:

51.57 g.

Explanation:

  • The balanced equation: <em>2Fe + 3S → Fe₂S₃,</em> it is clear that 2.0 moles of Fe react with 3.0 moles of S to produce 1.0 mole of Fe₂S₃.
  • We need to calculate the no. of moles of Fe₂S₃:

n = mas/molar mass = (96.0 g)/(207.9 g/mol) = 0.46 mol.

<em><u>Using cross multiplication we can get the no. of moles of Fe that isn eeded to produce 0.46 mol of Fe₂S₃:</u></em>

2.0 moles of Fe produces → 1.0 mol of Fe₂S₃.

<em>??? moles of Fe produces </em>→ 0.46 mol of Fe₂S₃.

∴ The no. of moles of Fe needed = (2.0 mol)(0.46 mol)/(1.0 mol) = 0.92 mol.

  • Now, we can get the mass of 0.92 mol Fe:

<em>mass = no. of moles x molar mass</em> = (0.92 mol)(55.845 g/mol) = <em>51.57 g.</em>

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