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Andre45 [30]
3 years ago
5

Roger started with 90 items in his MP3 collection. Each month, he buys 15 more MP3s to add to his collection. The number of MP3s

in his collection, P, is given by P = 15m + 90, where m is the number of months he has added 15 MP3s to his collection. How many MP3s will be in Roger’s account in 9 months?
A. 90
B. 105
C. 225
D. 315
Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

C 225

Step-by-step explanation:

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Y_Kistochka [10]

53 and 17

Step-by-step explanation:

If you add 53 and 17, you get 70.

If you subtract 17 from 53, you get 36. Hope this helps!

7 0
3 years ago
Solve the equation 18=n-18<br><br>n=_____​
Maksim231197 [3]

Answer:

36

Step-by-step explanation:

7 0
3 years ago
Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number
sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
Use long division to find the quotient below.
Tems11 [23]

Answer:

Step-by-step explanation:

2

x

2

+

5

x

+

3

=

(

x

+

1

)

(

2

x

+

3

)

Explanation:

2

x

2

+

5

x

+

3

=

2

x

2

+

2

x

+

3

x

+

3

=

2

x

(

x

+

1

)

+

3

(

x

+

1

)

=

(

x

+

1

)

(

2

x

+

3

)

[Ans]

7 0
3 years ago
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