Answer:
the new monthly plan is $106.25
(3,2),(-9,6)
slope = (6 - 2) / (-9 - 3) = -4/12 = -1/3
y = mx + b
slope(m) = -1/3
use either of ur points...(3,2)....x = 3 and y = 2
now we sub into the formula and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b
so ur equation is : y = -1/3x + 3 <==
<h3>a)
</h3><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>
<h2>
</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>
<h2>
</h2><h3>■Multiply the fractions</h3>
<h2>
</h2>
<h3>Hence, Quotient =
</h3>
<h3>b)
</h3><h3>■Convert the decimals into a fractions</h3>
<h2>
</h2><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>
<h2>
</h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>
<h2>
</h2><h3>■Multiply the fractions</h3>
<h2>
</h2><h3>Hence, Quotient is
</h3>
<h3>c)
</h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>
<h2>
</h2><h3>■Multiply the fractions</h3>
<h2>
</h2><h3>Hence, The Quotient is
</h3>
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
It would be much easier for me to help you pick the correct equation
if you would let me see the list of choices.
Since I can't see any of the choices, I'll just make up a few equations
that have the ordered pair (24, 6) as a solution:
Y = 0.25 x
Y = x - 18
Y = 0.5 x - 6
Y = 0.1 x + 3.6
