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schepotkina [342]
3 years ago
10

What is the total anion concentration (in mEq/L ) of a solution that contains 6.0 mEq/L Na + , 11.0 mEq/L Ca 2+ , and 1.0 mEq/L

Li + ?
Chemistry
1 answer:
lubasha [3.4K]3 years ago
5 0

24



Ddddd

Hope I helped

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In animals, nitrogenous wastes are produced mostly from the catabolism of _____. In animals, nitrogenous wastes are produced mos
RoseWind [281]

Answer:

Proteins and nucleic acids

Explanation:

Nitrogen compounds in animals that are no longer of use, or are in access are excreted from the animals body, and are thus called nitrogenous waste. These nitrogenous waste can be excreted in three different ways.

1. Ammonia

2. Urea

3. Uric acid

8 0
3 years ago
How many atoms of gold are in a pure gold coin weighing 12.0g?
grigory [225]
12.0g x 1 mol / 63.546g = 0.188839581mol 

<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
</span>
0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

<span>That should be your answer!

Hope it helps!
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3 0
3 years ago
A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
Lesechka [4]

Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

5 0
3 years ago
What role does the vulture playing this food web
musickatia [10]

Answer:

scavenger- eats dead carcasses

Explanation:

4 0
3 years ago
Write the word and balanced chemical equations for the reaction between:
Greeley [361]

Answer:

HCl + Ca(OH)2 = CaCl2 + H2O - Chemical Equation Balancer.

5 0
3 years ago
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