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Hunter-Best [27]
3 years ago
14

Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct

Chemistry
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

B. CO₂ and H₂O.

Explanation:

When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).

In the case of methane, the balanced reaction is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

With the above information in mind the correct answer is option B. CO₂ and H₂O.

When the combustion is incomplete, carbon monoxide (CO) is produced as well.

mestny [16]3 years ago
8 0

Answer:

B. CO₂ and H₂O!

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What makes calcium and nitrogen different list two differences
liberstina [14]

Answer:

the difference in electronegativity is so large (2.04) that the bonding electrons spend almost all their time on the nitrogen atom.

Explanation:

Because calcium loses 2 electrons to become Ca2+, and nitrogen gains 3 electrons to become N3−, you need two calcium atoms and three nitrogen atoms in order to form a neutral compound.

6 0
3 years ago
Describe endothermic vs. exothermic reactions in terms of product formation. (hint: what happens when products are formed?)
shusha [124]

Answer:

Endothermic reaction chemical equation

Reactnt A + Reactant B + Heat (energy) ⇒ Products

Exothermic reaction chemical equation

Reactnt A + Reactant B ⇒ Products + Heat (energy)

Explanation:

Endothermic Reaction

An endothermic reaction is a reaction that reaction that requires heat before it would take place resulting in the absorption of heat from the surrounding that can be sensed by the coolness of the reacting system

An example of an endothermic reaction is a chemical cold pack that becomes cold when the chemical and water inside it reacts

Exothermic Reaction

An exothermic reaction is one that rekeases energy to the surroundings when it takes place. This is as a result of the fact that the combined heat energy of the reactants is more than the chemical heat energy of the products. An example of an exothermic reaction is a burning candle

5 0
3 years ago
A sample of metal has a mass of 5. 2 g and absorbs 20. 0 j of energy as it is heated from 30. 0°c to 40. 0°c. What is the identi
kiruha [24]

The identity of the metal is copper.

<h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

Using the formula of specific heat

H = mcdT

Where, H = Heat absorbed

m = mass of the metal

c = specific heat capacity of the metal

dT = temperature change

Putting the values in the equation

20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)

c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)

c = 385 JKg-1°C-1

Thus, the metal is copper.

Learn more about specific heat

brainly.com/question/11297584

#SPJ4

6 0
2 years ago
- La siguiente tabla, expone cómo desciende la temperatura (T) del aire con la altitud(h): Temperatura (ºC) 15 13,5 12 10,5 9 Al
Mrrafil [7]

Answer:

k = -0.006.

T₀ = 15 °C

Explanation:

Hola.

En este caso, considerando la gráfica mostrada en el archivo adjunto, podemos evidenciar que los datos dados se comportan de manera lineal, por lo que basado en la ecuación, T=k*h+To, podemos calcular la pendiente que basicamente es igual a k, tomando dos puntos en la gráfica:

k=\frac{12-13.5}{750-500}=-0.0006

Además, el valor de la temperatura inicial se puede extraer de la tabla, dado que esta es cuando la altura es 0 m, es decir 15 °C.

¡Saludos!

8 0
3 years ago
A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after
choli [55]

Answer:

9.25

Explanation:

Let first find the moles of NH_4Cl and NaOH

number of moles of NH_4Cl = 0.40  mol/L × 200 ×  10⁻³L

= 0.08 mole

number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

= 0.04 mole

The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )

pH = 9.25

8 0
3 years ago
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