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VMariaS [17]
3 years ago
8

Angle Q measures 30 degrees. If angle Q is rotates 15 degrees, what is the measurement of angle Q?

Mathematics
1 answer:
wariber [46]3 years ago
3 0
Angle Q will have the same measurement as it did before, 30°.
Just because the angle is rotated shouldn't change its angle measure.
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The equation 3 X -6x=72 Has a solution between 4 and 5
kotegsom [21]
The answer is a negative number so it cant be between 4 & 5
8 0
3 years ago
select the inequality that represents the relationship desribed below the sum of three times a number and seven is greater than
solong [7]

Answer:

There are many combinations based on the number you chose to subtract from both sides.

Step-by-step explanation:

Let the number be x.

According to the question,

3 x+7 > 4 x

We get, 3 x+1=4 x-6, after subtracting 6 from both sides.

3 x+1=4 x-6

4 x- 3 x=6+1

x=7

You will get the same answer if you subtract 3 x or 7 or any other number from both sides.

Thank you!

7 0
3 years ago
What is 6 divided by 2/3 in simplest form<br> A. 4<br> B. 8<br> C. 9<br> D. 12
Helen [10]
6*(3/2)=9
so, the answer is c
5 0
3 years ago
Read 2 more answers
Which of the values shown are potential roots of f(x) = 3x3 â€"" 13x2 â€"" 3x 45? Select all that apply.
Verdich [7]

The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

And the accurate root is 3 it can be determined by using rules of the rational root equation.

<h2>Given that,</h2>

Function; \rm f(x) = 3x^3 - 13x^2 -3x + 45

<h3>We have to determine,</h3>

Which of the values shown are potential roots of the given equation?

<h3>According to the question,</h3>

Potential roots of the polynomial are all possible roots of f(x).

\rm f(x) = 3x^3 - 13x^2 -3x + 45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

\rm p=\dfrac{All\  the \ positive}{Negative\  factors \ of\  45}

\rm q=\dfrac{All\  the \ positive}{Negative\  factors \ of\  3}

The factor of the term 45 are,

\pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45

And The factor of 3 are,

\pm1, \ \pm3

All the possible roots are,

\dfrac{p}{q} = \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}

Now check for all the rational roots which are possible for the given function,

\rm f(x) = 3x^3 - 13x^2 -3x + 45\\\\ f(1) = 3(1)^3 - 13(1)^2 -3(1) + 45 = 3-13-3+45 = 32\neq 0\\\\ f(-1) = 3(-1)^3 - 13(-1)^2 -3(-1) + 45 =- 3-13+3+45 = 32\neq 0\\\\ f(3) = 3(3)^3 - 13(3)^2 -3(3) + 45 = 81-117-9+45 =0\\\\ f(-3) = 3(-3)^3 - 13(-3)^2 -3(-3) + 45 = -81+117+9+45 =-144\neq 0

Therefore, x = 3 is the potential root of the given function.

Hence, The potential roots of the function are, \pm1, \ \pm3, \ \pm5, \ \pm9,\  \pm15, \ \pm45,\  \pm \dfrac{1}{3},\  \pm \dfrac{5}{3}.

For more details about Potential roots refer to the link given below.

brainly.com/question/25873992

8 0
2 years ago
What is the area of the circle when the diameter is 2
mel-nik [20]

Answer:

3.14

Step-by-step explanation:

because its diameter that is 2, you divide it in half which should be one, that will be the radius. to get the area from the radius you multiply it by its self and multiply that by 3.14 which is the circumference of a circle.

7 0
4 years ago
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