I assume the heights are 160 ft and 1480 ft.
The two heights are unknown, so we will use variable h to help solve the problem.
The shorter building, building A, has height h.
Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.
Now we add our two heights to find the total height.
h + h + 160 is the total height.
We can write it as 2h + 160
We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.
2h + 160 = 1480
Subtract 160 from both sides
2h = 1320
Divide both sides by 2
h = 660
h + 160 = 820
Building A measures 660 ft.
building B measures 820 ft.
14×2÷7-3+9=10
Worked it out myslef and enjoy doing math.
Answer: each width = 10, each length = 21
Explanation: from the question we know that L=2w + 1 and we also know that a rectangle has the perimeter of 62 when we plug it in the equation we will get 62= 2(2w+1+w) we will multiply the 2 now and we will get 62=4w+2+2w we will combine like terms and we will minus two from both sides ending up with 60=6w we will divide six from both sides and we will get w=10 then we will use l=2w+1 to find the length and it will be 21
if we divide 20 by 12, we get a quotient of 1, and a remainder of 8.
