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g100num [7]
3 years ago
13

If xy +6e^y = 6e, find the value of y" at the point where x = 0

Mathematics
1 answer:
Andrews [41]3 years ago
4 0
I believe this would be the solution.
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I need help i don’t understand
suter [353]
The answer should be B, in other words 41
8 0
3 years ago
A bank offers a money market account paying 8.7​% interest compounded annually. A competing bank offers a money market account p
stich3 [128]
The answer is 8.5% interest compounded daily.

EXPLANATION

Regardless of your rate, the more often interest is paid, the more beneficial the effects of compound interest.

A daily interest account, which has 360 compounding periods a year, in this case, will generate more money than an account with an annual compounding, which has one compounding period per year.
5 0
3 years ago
The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
Besides 26 and 1, what is one factor of 26?
Ainat [17]
13 and 2, I think that is the only one left.

5 0
3 years ago
Read 2 more answers
How Do You Solve (8x+7)^3?
marysya [2.9K]
<span><span>(<span><span>8x</span>+7</span>)</span>*<span>(<span><span>8x</span>+7</span>)</span></span>*<span>(<span><span>8x</span>+7</span><span>)
</span></span><span>(<span><span>8x</span>+7</span>)</span><span>(<span><span><span>64<span>x^2</span></span>+<span>112x</span></span>+49</span><span>)
</span></span><span><span><span><span><span><span><span>(<span>8x</span>)</span><span>(<span>64<span>x^2</span></span>)</span></span>+<span><span>(<span>8x</span>)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(<span>8x</span>)</span><span>(49)</span></span></span>+<span><span>(7)</span><span>(<span>64<span>x^2</span></span>)</span></span></span>+<span><span>(7)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(7)</span><span>(49)
</span></span></span><span><span><span><span><span>512<span>x^3</span></span>+<span>896<span>x^2</span></span></span>+<span>392x</span></span>+<span>448<span>x^2</span></span></span>+<span>784x</span></span>+<span>343
</span>Answer:
<span><span><span>512<span>x^3</span></span>+<span>1344<span>x^2</span></span></span>+<span>1176x</span></span>+<span>343</span>

4 0
3 years ago
Read 2 more answers
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