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3 years ago

If JM = 5x – 8 and LM = 2x – 6, which expression represents JL?

Mathematics

1 answer:

Delvig [45]3 years ago

3 0

The green line is LM
The red line is JM
The blue point is at the coordinates (2/3, -14/3)

you'll have to excuse the way my graph looks. my graphing application on my computer is weird

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If 2x-10=4, what must x squelch to?

mr_godi [17]

Answer:

x=7

Step-by-step explanation:

2x-10=4 add 10 to both sides

2x=14 divide both sides by 2

x=7

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3 years ago

Need help please!!!! Brainiest if answered correctly!!!! No link, it will be reported!!

patriot [66]

The mean increases. When Deleware (2,000: 2) is included the mean must be divided by 9 instead of 8.

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2 years ago

In the past, the population proportion of consumers preferring orange juice with no pulp was equation. To test if this populatio

geniusboy [140]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

a) For the null hypothesis,

P = 0.45

For the alternative hypothesis,

P ≠ 0.45

b) For the decision rule, we would reject H0 if 0.1 > p value and accepth H0 if 0.1 < p value

Considering the population proportion, probability of success, p = 0.45

q = probability of failure = 1 - p

q = 1 - 0.45 = 0.55

Considering the sample,

Sample proportion, p = x/n

Where

x = number of success = 52

n = number of samples = 120

p = 52/120 = 0.43

c) We would determine the test statistic which is the z score

z = (p - P)/√pq/n

z = (0.43 - 0.45)/√(0.45 × 0.55)/120 = - 0.44

Recall, population proportion, P = 0.45

The difference between sample proportion and population proportion(P - p) is 0.45 - 0.43 = 0.02

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.45 - 0.02 = 0.43

the p for the right tail is 0.45 + 0.02 = 0.47

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.3336

We would double this area to include the area in the right tail of z = 0.44 Thus

p = 0.3336 × 2 = 0.67

d) Since alpha, 0.1 < than the p value, 0.67, then we would fail to reject the null hypothesis. Therefore, at a 1% level of significance, we do not have enough evidence to reject the null hypothesis

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3 years ago

HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined

tiny-mole [99]

Answer: Any real number x as long as $x \ne 0$ and $x \ne -\frac{2}{3}$

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

x = 0 or 3x+2 = 0 .... zero product property

x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

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3 years ago

Find the centre and radius for this circle , x^2+y^2=25

aliya0001 [1]

Answer:

centre = (0, 0 ), radius = 5

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 25 ← is in this form

with centre = (0, 0 ) and r = $\sqrt{25}$ = 5

3 0

3 years ago