9514 1404 393
Answer:
9.5°, yes
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
The distance opposite the angle of elevation is the plane's height, 500 m. The distance adjacent to the angle of elevation is the horizontal distance to the plane, 3 km = 3000 m. Then the angle is found from ...
tan(α) = 500/3000 = 1/6
α = arctan(1/6) ≈ 9.46°
The plane is approaching at an angle of 9.46°. It is safe to land, since that angle is less than 15°.
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<em>Additional comment</em>
The usual descent angle for most commercial air traffic is 3°. Some airport geography demands it be different (steeper). A higher descent angle can put undue stress on the landing gear.
It’s 25. Plug -2 into g, which is -5. Then plug -5 into f, which is 25.
Answer:
Step-by-step explanation:
we have
x-intercept (3,0) and y-intercept (0,-6)
step 1
Find the slope
The slope is
step 2
Find the equation of the line into point slope form
The equation is equal to
we have
substitute
----> equation of the line into point slope form
The base of 6 is the same, so add 1/2+1/2 =1
6^1 = 6
