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stiks02 [169]
4 years ago
12

What did Richard Maddox invent? Why was this important?

Computers and Technology
2 answers:
DerKrebs [107]4 years ago
4 0

Answer:

richard maddox created the first 35mm camera

Explanation:

Grade 10

liberstina [14]4 years ago
3 0

Answer:

Plates for photography

Explanation:

Hello! Mr. Richard Maddox invented plates for photography. They were important because it was an important item used in still photography, which was a big thing back then, and sometimes still is today! Have an awesome day!

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How to beat level 50 in give up robot 2
LiRa [457]

Answer:

just follow the steps and and become tough calm but tough

3 0
3 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
The most common type of database is a __________ database. question content area bottom part 1 a. relational b. normalized c. sa
sashaice [31]

The most common type of database is a <u>relational  </u>database.

<h3>What is relational database?</h3>

A relational database is seen as a set up of information that is known to be put together data in a way that is predefined in its relationships and it is one where data is saved in one or more tables.

Note that it is one that do makes it easy to see and know how different data structures links to each other. Hence, The most common type of database is a <u>relational  </u>database.

Learn more about database from

brainly.com/question/518894

#SPJ1

7 0
2 years ago
Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
enyata [817]

Answer:

The method in C++ is as follows:

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

   double baseArea = calcBaseArea(baseLength, baseWidth);

   double volume = baseArea * pyramidHeight;

   return volume;    

}

Explanation:

This defines the calcPyramidVolume method

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

This calls the calcBaseArea method to calculate the base area of the pyramid

   double baseArea = calcBaseArea(baseLength, baseWidth);

This calculates the volume

   double volume = baseArea * pyramidHeight;

This returns the volume

   return volume;  

}

<em>See attachment for complete program that include all methods that is required for the program to function.</em>

5 0
3 years ago
What is the nearest ten cents of 453.56
Nutka1998 [239]

Answer:

453.6

Explanation:

It is 453.6 because you are rounding to the nearest ten cents place and in the number 453.56, 5 is in the ten cents place or the tenths place so you look at the number to its right, which is 6 and when you round, numbers 0-4 cause the rounding number to stay the same, numbers 5-9 cause them to go up one. In this situation, it is six so the number 5 would go up one, making it 6 and then you get rid of the numbers to the right side making it 453.6

3 0
3 years ago
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