All categories

3 years ago

I need help a b c d

Chemistry

1 answer:

jok3333 [9.3K]3 years ago

6 0

Answer:

Option-A (XY)

Explanation:

In this problem one should focus on the number of valence electrons present in each atom. Remember that in lewis structure the dots on an atom always show the valence shell electrons. In given statement;

The,

X has one valence electron. It means that it can loose this single electron to attain the noble gas configuration i.e.

X° → X⁺ + 1e⁻

Similarly,

Y have seven valence shell electrons. Therefore, in order to complete the octet this atom will gain one electron i.e.

::Y:° + 1 e⁻ → Y⁻

Hence, we can conclude that X got stabilized by losing one electron and Y got stabilized by gaining one electron therefore, only one of each is required to form an ionic compound i.e.

You might be interested in

Calculate the pH of a solution that is 0.147M HCl

Mariana [72]

Answer:

pH = 0.832

Explanation:

pH is given by the formula;

pH = - log [H+]

in this case we are given 0.147 M HCl

HCl is a strong acid and therefore completely dissociates to give out H+ ions,

Therefore; [H+] = [HCl] = 0.147 M

Hence;

pH = - log 0.147 M

3 0

3 years ago

Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=

IgorC [24]

Answer: $\Delta H^0=+0.3kJ/mol$ .

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$S_{rhombic}+O_2(g)\rightarrow SO_2(g)$ $\Delta H^0_1=-296.06kJ$ (1)

$S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ$ (2)

The final reaction is:

$S_{rhombic}\rightarrow S_{monoclinic}$ $\Delta H^0_3=?$ (3)

By subtracting (1) and (2)

$\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ$

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0

3 years ago

Because a water molecule has a negative end and a positive end, it displays_____?

Nezavi [6.7K]

The unequal sharing of electrons gives the water molecule a slight negative charge near its oxygen atom and a slight positive charge near itshydrogen atoms. When a neutral molecule has a positive area at one end and a negative area at the other, it is a polar molecule.

3 0

4 years ago

Read 2 more answers

How many moles does 21. 7 L of gas at STP represent?

Oduvanchick [21]

Answer:

.96875 moles

Explanation:

22.4 liters per mole at STP for a gas

21.7 / 22.4 = .96875 moles

3 0

2 years ago

What do the rows of the periodic table indicate?

Tanya [424]

Answer:

The rows on the periodic table are called periods. All the elements in a period have valence electrons in the same shell. The number of valence electrons increases from left to right in the period. When the shell is full, a new row is started and the process repeats.

Explanation:

hope this helps..

3 0

3 years ago