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4 years ago

Calculate the atmospheric pressure if the boiling point of water is 81 degrees Celsius.

2 answers:

8 0

To calculate the atmospheric pressure at a specific boiling point of water, we use the steam table or the Antoine equation. From steam table via interpolation, at 81 C, the pressure where saturation occurs is the atmospheric pressure. The atmospheric pressure is 369.7 mm Hg or 0.4864 atm.

iren2701 [21]4 years ago

6 0

Answer : The atmospheric pressure of water if boiling at 81 °C will be 369 mmHg.

Explanation : The vapor pressure of boiling water can be calculated using the Antoine Equation:

log P = A - $[\frac{B}{ C + T} ]$ ,

where P is the pressure in mmHg,

A = 8.07131,

B = 1730.63

C = 233.426

and T = temperature in °C (81°C)

Substituting the given values, we get,

Log P = 8.07131− $[\frac{1730.63}{233.426 + 81}]$

Therefore, Log P =8.07131 − 5.5041 = 2.567.

Now, P = $(10^{2.567} )$ =369 mmHg.

Hence, the atmospheric pressure will be 369 mmHg.

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Silver chloride is virtually insoluble in water so that the reaction appears to go to completion. How many grams of solid NaCl m

masya89 [10]

Answer:

0.535 g

Explanation:

The reaction that takes place is:

NaCl + AgNO₃ → AgCl + NaNO₃

First we calculate how many AgNO₃ moles are there in 25.0 mL of a 0.366 M solution, using the definition of molarity:

Molarity = moles / liters

moles = Molarity * liters

Converting 25.0 mL to L ⇒ 25.0 / 1000 = 0.025 L

moles = 0.366 M * 0.025 L = 0.00915 mol AgNO₃

Then we convert AgNO₃ moles into NaCl moles:

0.00915 mol AgNO₃ * $\frac{1molNaCl}{1molAgNO_3}$ = 0.00915 mol NaCl

Finally we convert NaCl moles into grams, using its molar mass:

0.00915 mol NaCl * 58.44 g/mol = 0.535 g

4 0

3 years ago

Write the ground state electron configuration of zn using the noble-gas shorthand notation.

V125BC [204]

Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
1s², 2s², 2p⁶, 3s², 3p⁶ = Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,

[Ar] 4s², 3d¹⁰

8 0

3 years ago

The decay of radioisotopes is a typical first order reaction. The half-life of carbon-14 (14C) is a radioactive isotope that dec

Nady [450]

Answer:

By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Half-life: 5,730 ± 40 years

Names: carbon-14, C-14, radiocarbon

Isotope mass: 14.003241 u

8 0

3 years ago

Which is more stable? half filled or full filled? Why is it more stable?

olchik [2.2K]

A full filled atom is more stable than the half filled atom. This is because it has an equal number of protons and electrons. The protons cancel out the electrons and thus giving it a net charge of zero. It cannot be further ionized.

4 0

4 years ago

A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3

IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cl₂: 4 moles
P: 2 moles
PCl₃: 1 mole
PCl₅: 1 mole

The molar mass of the compounds is:

Cl₂: 70.9 g/mole
P: 31 g/mole
PCl₃: 137.35 g/mole
PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
P: 2 moles× 31 g/mole= 62 grams
PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

$mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}$

mass of Cl₂= 96.97 grams

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

$mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}$

mass of PCl₃= 38.26 grams

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

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