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sammy [17]
3 years ago
5

potassium and chlorine react to form potassium chloride. a.it is a redox reaction,explain why. b.see if u can write a balanced e

quation for it.​
Chemistry
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

<em>K</em><em>+</em><em>Cl</em><em /><em>KCl</em>

Explanation:

because the reaction is between metal Potassium and Non-metal Chlorine

Ber [7]3 years ago
5 0

Answer:

Explanation:

a) It is a redox reaction because KCl is an ionic compounds with K having a + charge and Cl having a - charge. Originally, both have an oxidation state of 0 and not K has 1+ and Cl has 1-. Therefore, one species was oxidized and one was reduced which is indicative of a redox reactions.

b)

2K + Cl2 => 2KCl

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I don't get your question
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At equilibrium, no chemical reactions take place. true or false
arsen [322]
False. At equilibrium, the rate of forward reaction is equal to the rate of backward reaction. The net concentration of both products and reactants won't change, but the reactions still take place.
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A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
What is the balanced chemical equation for the reaction of aqueous sodium hydroxide and sulfuric acid?
Andrews [41]

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

6 0
3 years ago
3. How many grams of aluminum can be heated from 90°C to 120°C if 500 J of heat energy are applied?
IgorLugansk [536]

<u>We are given:</u>

Initial Temperature = 90°c

Final Temperature = 120°c

Heat applied(ΔH) = 500 Joules

Specific heat(c) = 0.9 Joules / g°C

Mass of Aluminium(m) = ?

<u>Change in temperature:</u>

ΔT = Final temp. - Inital Temp.

ΔT = 120 - 90

ΔT = 30°c

<u>Calculating the mass:</u>

We know the formula:

ΔH = mcΔT

replacing the values:

500 = m(0.9)(30)

500 = m(27)

m = 500/27

m = 18.52 grams

5 0
3 years ago
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