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Veronika [31]
2 years ago
11

How many moles does 21. 7 L of gas at STP represent?

Chemistry
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

.96875 moles

Explanation:

22.4 liters per mole at STP for a gas

21.7 / 22.4 = .96875 moles

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Which shows the conversion of 8.93 × 10-2 grams to milligrams?
Allushta [10]
The prefix milli means thousand so the correct conversion factor is 1000mg/g
4 0
3 years ago
Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of 1010 g/L. If vinegar is 0.80
Damm [24]

Answer:

4.8 %

Explanation:

We are asked the concentration in % by mass, given the molarity of the solution and its density.

0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:

MW acetic acid = 60.0 g/mol

mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g

mass of solution = 1000 cm³ x 1.010 g/ cm³      (1l= 1000 cm³)

                            = 1010 g

% (by mass) = 48.00 g/ 1010 g  x 100 = 4.8 %

6 0
3 years ago
Less energy was entering Earth's
ololo11 [35]

Answer:

The temperatures on Earth increase

Explanation:

more energy results in more heat.

6 0
3 years ago
How many moles of magnesium, Mg, are there in 4.75 grams of magnesium?
Nina [5.8K]
Molar mass Mg = 24.3 g/mol

1 mole mg ------------ 24.3 g
?? moles mg --------- 4.75 g

4.75 x 1 / 24.3 => 0.195 moles of Mg

hope this helps!
3 0
3 years ago
What is the percent composition of hydrogen in vinegar (CH3COOH)?​
barxatty [35]

Answer:

                      %H  = 6.72 %

Explanation:

                   Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

So,

Percent composition of Hydrogen will be given as,

         %H  =  Total mass of H / Molecular Mass of Acetic Acid × 100

So,

Total Mass of H  =  1.01 × 4 = 4.04 g

Molecular Mass of Acetic acid  =  60.052 g/mol

Putting values in above formula,

         %H  =  4.04 g/mol ÷ 60.052 g/mol × 100

         %H  = 6.72 %

6 0
3 years ago
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