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alexgriva [62]
3 years ago
14

What is 1100 increased by 4% ?

Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0
1100 increased by 4% is 24960.
Nady [450]3 years ago
5 0
1,144
You first take 1,100, multiply it by .04, and you get 44. Add 44 to 1,100 and you get your answer.
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64 POINTS
Mekhanik [1.2K]
L(t)=9-0.5t   
t=time in hours,
L(t)=length of candle at time t

(A) substitute t=1,2,3,4,5,6 respectively to get
(1,8.5)
(2,8)
(3,7.5)
(4,7)
(5,6.5)
(6,6)

(B) it is a function because none of the x-values duplicate, (nor the y-values).

(C) If the rate changes to 0.45 "/hr, the relation is still linear.
All linear function with finite slope are functions.

7 0
3 years ago
Read 2 more answers
On a piece of paper, use a protractor to construct a triangle with angle measures of 40 degrees and 60 degrees.
Andru [333]

Answer:

80

Step-by-step explanation

Well every triangle has to equal 180 degrees.

So you would add the two degrees you already have, which on this one you would get 100.

Then, you would subtract that number from 180 to get 80.


Hope this helps you!!

8 0
3 years ago
Read 2 more answers
What number is 100,000 more than 75,000 and explain how u got answer
alina1380 [7]
100,000 + 75,000 = 175,000. To get the answer, you add the two.
6 0
3 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

#SPJ1

7 0
2 years ago
The angle measures of a triangle are shown in the diagram.
STALIN [3.7K]

Answer:

Step-by-step explanation:

B

5 0
3 years ago
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