1 point
2 answers:
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Answer:
Step-by-step explanation:
we know that
The area of the figure is equal to the area of an isosceles triangle (has two equal sides) plus the area of a rectangle
step 1
Find the area of the triangle
The area of the triangle is equal to
we have
To find out the height of the triangle Apply the Pythagorean Theorem
solve for h
<em>Find the area of triangle</em>
step 2
Find the area of rectangle
The area of rectangle is equal to
we have
substitute
step 3
Find the area of the figure
Adds the areas
3:5 ratio mean there are 8 "parts" (3 + 5 = 8)
The distance between the x-coordinates is |-3 - 5| = 8.
So each "part" is 8/8 = 1 unit long in the x-direction.
You want I to be 3(1) = 3 units from D, so the x-coordinate of I is -3 + 3 = 0.
Same deal for y.
|2 - 5| = 3 is the distance between D and E
Each part is 3/8.
3(3/8) = 9/8
2 + 9/8 = 25/8
So the point I is (0, 25/8)
The distance between the x-coordinates is |-3 - 5| = 8.
So each "part" is 8/8 = 1 unit long in the x-direction.
You want I to be 3(1) = 3 units from D, so the x-coordinate of I is -3 + 3 = 0.
Same deal for y.
|2 - 5| = 3 is the distance between D and E
Each part is 3/8.
3(3/8) = 9/8
2 + 9/8 = 25/8
So the point I is (0, 25/8)