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Gnom [1K]
3 years ago
9

1 point

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
6 0
18n+4.4m I don’t know if this is right but I don’t understand the information you gave me because the numbers are scrambled
amid [387]3 years ago
4 0
18n+4.4m should be it
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kow [346]

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false

Step-by-step explanation:

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Fofino [41]

Domain:x\neq-3\\\\\dfrac{2x}{x+3}\leq3\qquad\text{subtract 3 from both sides}\\\\\dfrac{2x}{x+3}-3\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3(x+3)}{x+3}\leq0\\\\\dfrac{2x}{x+3}-\dfrac{3x+9}{x+3}\leq0\\\\\dfrac{2x-(3x+9)}{x+3}\leq0\\\\\dfrac{2x-3x-9}{x+3}\leq0\\\\\dfrac{-x-9}{x+3}\leq0\Rightarrow(x+3)(-x-9)\leq0\\\\x=-3,\ x=-9\\\\x\in(-\infty,\ -9]\ \cup\ (-3,\ \infty)

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aniked [119]
The best and most correct answers among the choices provided by the question are:

<span>▢A. -2x+3y=-15
▢B. y=2/3x-5</span>

y = mx + b. where m is the slope<span> of the line and b is the y-</span>intercept<span> of the line, or the y-coordinate of the point at which the line crosses the y-axis. To write an equation in </span>slope-intercept form<span>, given a graph of that equation, pick two points on the line and use them to find the </span>slope<span>.</span>

I hope my answer has come to your help. God bless and have a nice day ahead!
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