Answer:
Step-by-step explanation:
Step 1: Subtract 3x from both sides.
5x−4−3x=3x+18−3x
2x−4=18
Step 2: Add 4 to both sides.
2x−4+4=18+4
2x=22
Step 3: Divide both sides by 2
2x/2= 22/2
x= 11
Answer: When t = 4.25 R(t) = D(t)
This tells you that at 4.25 seconds into their flights, both the Rocket and the Drone were at a height of 20 feet.
Step-by-step explanation: The point where the two graphed lines cross is where the values are equal.
The Drone has been hovering at 20 feet between 2 and 5 seconds. The Rocket passed through that height for a brief (millisecond) time as it was falling back to the ground.
Without grid lines it is my best estimation (using a ruler to create a verticla line from the intersection of the lines to the time scale) that t = 4.25. It is between 4 and 4.5 seconds.
I think it's 10 because the perimeter is 30 and I divided the 30 by 3 because there's 3 rectangles and the answer I got is 10. Not 100% accurate but yea
8 ft wide, 12 ft long......so if u want it 2 ft wide, u have a scale factor of 1/4.
that means ur length will be 12 * 1/4 = 12/4 = 3 ft long
A = L * W
A = 3 * 2
A = 6 square ft <==
three-dimensional graphs wouldn´t give you the right information but two-dimensional graphs would give you the actual size of the shape.
