Answer:
Answers are in bold type
Step-by-step explanation:
f(x) = 
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.  
The  range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57  and increases when 57 > x > ∞
The x - intercepts:   = 0
 = 0
                                 x(x - 114x) = 0
                                 x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept.  So, 0^2 - 114(0) = 0
y-intercept is (0, 0)