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2 years ago

Which statement best describes the electrons in this illustration ?

Physics

2 answers:

Nonamiya [84]2 years ago

7 0

A. electrons are negatively charged outside nucleus

koban [17]2 years ago

5 0

A is obviously true
the electrons are located around the nucleus (nucleus is made up of protons and neutrons.)
electrons are negatively charge particles
protons are positively charged particles
neutrons are neutral
hope this helps

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Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth’s center. Satellite A is to o

Vera_Pavlovna [14]

Answer:

Explanation:

Orbital radius of satellite A , Ra = 6370 + 6370 = 12740 km

Orbital radius of satellite B , Rb = 6370 + 19110 = 25480 km

Orbital potential energy of a satellite = - GMm / r where G is gravitational constant , M is mass of the earth and m is mass of the satellite

Orbital potential energy of a satellite A = - GMm / Ra

Orbital potential energy of a satellite B = - GMm / Rb

PE of satellite B /PE of satellite A

= Ra / Rb

= 12740 / 25480

= 1 / 2

b ) Kinetic energy of a satellite is half the potential energy with positive value , so ratio of their kinetic energy will also be same

KE of satellite B /KE of satellite A

= 1 / 2

c ) Total energy will be as follows

Total energy = - PE + KE

- P E + PE/2

= - PE /2

Total energy of satellite B / Total energy of A

= 1 / 2

Satellite B will have greater total energy because its negative value is less.

5 0

2 years ago

The mass of a car is 2,400 kg and its momentum is 22,240 kg<br> m/s. What is its velocity?

Crazy boy [7]

Answer:

9.27

Explanation:

6 0

2 years ago

At a height of ten meters above the surface of a freshwater lake, a sound pulse is generated. The echo from the bottom of the la

konstantin123 [22]

Answer:

Explanation:

Velocity of sound in air at 20 degree = 343 m/s

Velocity of sound in water at 20 degree = 1470 m/s

Time taken in to and fro movement in air

=( 2 x 10) / 343 = 0.0583 s

Rest of the time is

.171 - .0583 = .1127 s

This time is taken to cover distance in water. If d be the depth of lake

2d / velocity = time taken

2 d / 1470 = .1127

d = 82.83 m

5 0

2 years ago

What if is a forecasting game, below are actions on your document and all you have to do is predict what will happen after the a

Talja [164]

1. Triple click on the paragraph.

By extension, the triple click can allow you to select a line and the quadruple click a section (paragraph).

2. Pressing Ctrl + A.

Ctrl+A | Ctrl+E: Select all. Depending on the programs and the translations, it will be one or the other.

3. Double click within the word.

In most text editors, a double-click on a word selects it in its entirety.

4. Pressing key combinations Shift + arrow key.

If you press one of the arrow keys with the Shift key pressed, you can select a section of text.

5. Pressing key combinations Ctrl + End.

Ctrl + End: Go to the end of the document or window.

Ctrl + Home: Go to the beginning of the document or window.

Ctrl + Insert: Copy the selected text.

Please mark me as brainliest.

<h3>➥ I hope I have helped you, greetings! </h3><h3>Atte: ღTheGirlSadღ </h3>

7 0

1 year ago

Read 2 more answers

Steam enters a one-inlet, two-exit control volume at location (1) at 360°C, 100 bar, with a mass flow rate of 2 kg/s. The inlet

yaroslaw [1]

Answer:

The inlet velocity is 21.9 m/s.

The mass flow rate at reach exit is 1.7 kg/s.

Explanation:

Given that,

Mass flow rate = 2 kg/s

Diameter of inlet pipe = 5.2 cm

Fifteen percent of the flow leaves through location (2) and the remainder leaves at (3)

The mass flow rate is

$m_{2}=0.15\times2$

We need to calculate the mass flow rate at reach exit

Using formula of mass

$m_{3}=m_{1}-m_{2}$

$m_{3}=2-0.15\times2$

$m_{3}=1.7\ kg/s$

We need to calculate the inlet velocity

Using formula of velocity

$v=\dfrac{m}{\rho A}$

Put the value into the formula

$v=\dfrac{2}{42.868\times\dfrac{\pi}{4}\times(5.2\times10^{-2})^2}$

$v=21.9\ m/s$

Hence, The inlet velocity is 21.9 m/s.

The mass flow rate at reach exit is 1.7 kg/s.

7 0

3 years ago