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3 years ago

Which statement describes the energy involved in diffusion?

Physics

2 answers:

artcher [175]3 years ago

7 0

Answer:

Diffusion requires energy only to move material through the cell membrane.

Explanation:

mrs_skeptik [129]3 years ago

3 0

Answer:

Diffusion requires energy only to move material out through the cell membrane.

Explanation:

Hope this helped! :)

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A 1.5 kg ball is thrown upward at 10 m/s. What is its velocity when it is 2 m above the release point?

Anestetic [448]

Answer:

7.75m/s or $2\sqrt{15}m/s$

Explanation:

m = 1.5kg

u= 10m/s

s = 2m

a = $10m/s^{2}$

v = ?

acceleration due to gravity is negative when an object is going up because the force of gravity reduces the speed of the object

using the formula ;

$v^{2} = u^{2} - 2as$ since the object is moving upwards (negative acceleration)

= 100 - 2(10)(2)

100 - 40

$v^{2}$ = 60

v = $\sqrt{60}$

= 7.75m/s

5 0

3 years ago

When a baseball hits a

frez [133]

The reaction force is the glove pushing against the ball because the reaction force would be the ball pushing onto the glove.

Hope that helps :)

3 0

3 years ago

The particles ejected from the sun during a coronal mass ejection is called

ipn [44]

Answer:

Plasma

Explanation:

A Coronal Mass Ejection (CME) is an outburst of energy that occurs near the outer part of the sun's atmosphere which causes a production of plasma along with a magnetic field.

The outermost part of the sun's atmosphere is called the Solar Corona Although difficult to see, the corona can be seen during a total solar eclipse.

Plasma from CME are clouds of magnetized electrically charged particles which the solar wind causes to travel at a speed of 1.6 million km/hr.

7 0

3 years ago

Light that has a wavelength of 600 nm strikes a metal surface, and a stream of electrons is ejected from the surface. If light o

Anni [7]

Answer:

The maximum kinetic energy of the electrons emitted from the surface will be greater.

Option 3 is correct.

Explanation:

Given that,

Wavelength $\lambda_{1}=600\ nm$

Wavelength $\lambda_{2}=500\ nm$

We need to calculate the energy for first wavelength

Using formula of energy

$E=hf$

$E=h\dfrac{c}{\lambda}$

Put the value into the formula

$E_{1}=6.67\times10^{-34}\times\dfrac{3\times10^{8}}{600\times10^{-9}}$

$E_{1}=3.33\times10^{-19}\ J$

We need to calculate the energy for second wavelength

Put the value into the formula

$E_{2}=6.67\times10^{-34}\times\dfrac{3\times10^{8}}{500\times10^{-9}}$

$E_{2}=4.002\times10^{-19}\ J$

So, E₂>E₁

Hence, The maximum kinetic energy of the electrons emitted from the surface will be greater.

8 0

3 years ago

A 1.0-in.-diameter hole is drilled on the centerline of a long, flat steel bar that is 1 2 thick and 4 in. wide. The bar is subj

Dominik [7]

Answer:

The answers are

The average stress = 20000 lb/in²

The maximum tensile stress immediately adjacent to the hole

= 31076.92 lb/in²

Explanation:

To solve the question we have

Weight of tensile load = 30,000 lb

Width of steel bar = 4 in

Thickness of steel bar = 1/2 in

Average Stress = Force/Area

Size of hole drilled = 1.0 in diameter

Available width at cross section where the 1.00 in diameter hole is drilled =

(4 - 1) in = 3 inches

Cross sectional area at the point of reduced cross section due to the drilled hole = Width × Thickness (Since the item is a flat bar)

= 3 in × 1/2 in = 1.5 in²

Therefore Stress = (30000 lb)/(1.5 in²) = 20000 lb/in²

the maximum tensile stress immediately adjacent to the hole.

Bending stress = $\sigma_B= \frac{M_y}{I}$ where $I = \frac{(0.5^2 + 4^2)}{12}$

0.5*30000/I = 11076.92 lb/in²

Max stress = 31076.92 lb/in²

8 0

3 years ago

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