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USPshnik [31]
3 years ago
15

State joole's law ofheating and verifyexperimentally​

Physics
1 answer:
diamong [38]3 years ago
6 0

Answer:

Joule's law is verified using Joule's calorimeter. .

Explanation:

Two thirds of the volume of the calorimeter is filled with water. The calorimeter is enclosed in a wooden box to minimise loss of heat. A battery (Bt), a key (K), a rheostat (Rh) and an ammeter (A) are connected in series with the calorimeter

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What are the set of equations called that can be used to quantify motion in the case of uniform acceleration?
KATRIN_1 [288]
The kinematic equations are used to <span>quantify motion in the case of uniform acceleration.

The other name is : SUVAT equations, where the letters signify: 
 displacement (s),
initial velocity (u),
 final velocity (v),
acceleration (a), and
 time (t).

There are three equations are attached in the picture: </span>

7 0
4 years ago
True or false Carbon in the form of carbon dioxide is needed for both processes of photosynthesis and cellular respiration True
Anna007 [38]

Yes carbon dioxide is needed for photosynthesis while cellular respiration needs oxygen and dispurses carbon dioxide

5 0
3 years ago
The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these
harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

3 0
4 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat
N76 [4]

Answer:

p_k=\sqrt{p_x^2+p_y^2}}

Explanation:

Apply the momentum in each direction knowing that the impact is at the same time for the pieces so

p_x=m_1*v_1

p_x=200g*2.0m/s=0.4kgm/s

p_y=m_2*v_2

p_y=235g*1.5m/s=0.3525kgm/s

So the momentum in the other piece can be find knowing that

p_x^2+p_y^2=p_k^2

So:

p_k=\sqrt{p_x^2+p_y^2}}

p_k=\sqrt{0.4^2+0.3525^2}}=\sqrt{0.2842 kg^2*m^2/s^2}

p_k=0.5331kg*m/s

To find the velocity knowing the mass

p_k=m_k*v_k

v_k=\frac{p_k}{m_k}=\frac{0.5331 kg*m/s}{0.10kg}

v_k=5.331 m/s

4 0
3 years ago
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