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2 years ago

15

State joole's law ofheating and verifyexperimentally

1 answer:

diamong [38]2 years ago

6 0

Answer:

Joule's law is verified using Joule's calorimeter. .

Explanation:

Two thirds of the volume of the calorimeter is filled with water. The calorimeter is enclosed in a wooden box to minimise loss of heat. A battery (Bt), a key (K), a rheostat (Rh) and an ammeter (A) are connected in series with the calorimeter

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What is the weight of a dust particle

Alexandra [31]

Answer:

The mass of a dust particle is 7.53 x 10^-10 kg. (Hope it helped.)

Explanation:

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2 years ago

Would the springs inside a bathroom scale be more compressed or less compressed if you weighed yourself in an elevator that was

Ber [7]

More compressed. moving up = apparent weight (i.e., your norma force) is greater. this means you’ll weighr more and push those springs down even more than you would at rest.

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2 years ago

The depth of the Pacific Ocean in the Mariana Trench is 36,198 ft. What is the gauge pressure at this depth

FinnZ [79.3K]

Answer:

the pressure at the depth is 1.08 × $10^{8}$ Pa

Explanation:

The pressure at the depth is given by,

P = h $\rho$ g

Where, P = pressure at the depth

h = depth of the Pacific Ocean in the Mariana Trench = 36,198 ft = 11033.15 meter

$\rho$ = density of water = 1000 $\frac{kg}{m^{3} }$

g = acceleration due to gravity ≈ 9.8 $\frac{m}{s^{2} }$

P = 11033.15 × 9.8 × 1000

P = 1.08 × $10^{8}$ Pa

Thus, the pressure at the depth is 1.08 × $10^{8}$ Pa

4 0

3 years ago

At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4 T, pointing 75° below the horizontal in a north-south plane. A

saveliy_v [14]

Answer with Explanation:

We are given that

Magnetic field,B= $0.6\times 10^{-4} T$

$\theta=75^{\circ}$

Length of wire,l=15 m

Current,I=19 A

a.We have to find the magnitude of magnetic force and direction of magnetic force.

Magnetic force,F= $IBlsin\theta$

Using the formula

$F=0.6\times 10^{-4}\times 15\times 19sin75$

$F=16.5\times 10^{-3} N$

Direction= $tan\theta=cot(90-75)=tan15^{\circ}$

$\theta=15^{\circ}$

15 degree above the horizontal in the northward direction.

5 0

2 years ago

Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al ca

Nesterboy [21]

Answer:

$0.741\ \text{m/s}^2$

Explanation:

v = Velocidad final = $40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}$

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2$

La aceleración del camión en el primer intervalo de tiempo es $0.741\ \text{m/s}^2$ .

4 0

3 years ago