Answer:
See explaination
Explanation:
#include <iostream>
using namespace std;
class Circle{
// private member variable named radius
private:
double radius;
// get function for radius
public:
double getRadius(){
return radius;
}
// set function for radius
void setRadius(double rad){
radius=rad;
}
// returning area = 3.14159 * radius * radius
double getArea(){
return (3.14159 * radius * radius);
}
};
// Sample run
int main()
{
// Declaring object of Circle
Circle myCircle;
myCircle.setRadius(5);
// printing radius of circle
cout<<"Radius of circle is: "<<(myCircle.getRadius())<<endl;
// printing area of circle
cout<<"Area of circle is: "<<(myCircle.getArea())<<endl;
return 0;
}
Isn't it B because the x is increasing by .75 and y is deceasing by 2.5
Answer:
your a legend you can do it just pleave
Explanation:
:)
Answer:
Here is the constructor:
public Square(double s)
{ //constructor name is same as class name
sideLength = s; } //s copied into sideLength field
Explanation:
The above constructor is a parameterized constructor which takes a double type variable s as argument. The name of constructor is same as the name of class.This constructor requires one parameters. This means that all declarations of Square objects must pass one argument to the Square() constructor as constructor Square() is called based on the number and types of the arguments passed and the argument passed should be one and of type double.
Here is where the constructor fits:
public class Square {
private double sideLength;
public Square(double s)
{
sideLength = s; }
public double getArea() {
return sideLength * sideLength;}
public double getSideLength() {
return sideLength; } }
The correct answer choice would be letter B.
I hope that this helps !
