A(n) _____ is a common output device for hard copy.

Describe one difference and one similarity between science and pseudoscience.

irakobra [83]

A scientific experiment is repeatable. Pseudoscience makes claims that cannot be either confirmed or denied. Both seem to want to explain our experiences and broaden our understanding. Science, as a working method, employs basic principles such as objectivity and accuracy to establish a finding. It often also uses certain admitted assumptions about reality, assumptions that must eventually support themselves and be proven, or the resulting finding fails verification. Pseudoscience, however, uses invented modes of analysis which it pretends or professes meet the requirements of scientific method, but which in fact violate it's essential attributes. Many obvious examples of pseudoscience are easy to identify, but the more subtile and herefore more insidious and convincing cases.

6 0

3 years ago

onsider a file system on a disk that has both logical and physical block sizes of 512 bytes. assume that the information about e

anygoal [31]

For three disk allocation strategies (contiguous, linked, and indexed),

in this case, the physical blocks must be read from the disk are 1,4 and 2 respectively.

In the disk, every block has a sequential number. The majority of disks today do logical I/O in hardware. Physical I/O is seldom ever required of operating systems today.

File access uses virtual I/O. Similar to disk logical I/O is disk virtual I/O. The distinction is that with virtual I/O, as opposed to physical I/O, the blocks that make up a file are

You could want to transfer from virtual block 10 to virtual block 4 in a contiguous allocation. Since the file is contiguous and you are at logical block 10 + Z, block four can be accessed by reading logical block 4 + Z. Without any intermediaries, that can be done directly.

Each block in the linked structure has 511 bytes of data and one byte that serves as an offset to the following block.

Read the first block, determine the offset to the second block, read the second block, determine the offset to the fourth block, and then read the fourth block in order to gain access to the fourth block.

If blocks are numbered from 1 to 10, then then is the "4" correct. The remainder of the solutions, however, make the assumption that block numbering begins at 0, using division to obtain offsets.

Assume there is a contiguous index for the indexed way of allocating files. Once more, it is assumed that each offset in the index is one byte in size.

Let's say that Z serves as the index's origin. Then, the byte at block Z + 3 DIV 512 and the offset at 3 MOD 512 (3 = 4 - 1) make up the entry for block 4 (numbered 1 to 4).

You must read the index and the data block in order to locate the block (2 reads).

To learn more about disk allocation strategies click here:

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4 0

1 year ago

"Which layer of the OSI seven-layer model keeps track of a system's connections to send the right response to the right computer

ExtremeBDS [4]

Answer:

The Session layer (Layer 5)

Explanation:

The OSI (Open Systems Interconnection) seven-layer model is a reference model that explains how devices (or applications) communicate over the network. The model consists basically of seven different layers which are;

i. Layer 1 or the physical layer

ii. Layer 2 or the data-link layer

iii. Layer 3 or the network layer

iv. Layer 4 or the transport layer

v. Layer 5 or the Session layer

vi. Layer 6 or the presentation layer

vii. Layer 7 or the application layer.

Out of the seven layers, the session layer (layer 5) keeps track of a system's connections to send the right response to the right computer by setting up, coordinating and managing these connections. It controls, establishes and maintains the connection between multiple computers or applications on a computer.

8 0

3 years ago

Write a function addUpSquaresAndCubes that adds up the squares and adds up the cubes of integers from 1 to N, where N is entered

avanturin [10]

Answer:

All functions were written in python

addUpSquaresAndCubes Function

def addUpSquaresAndCubes(N):

squares = 0

cubes = 0

for i in range(1, N+1):

squares = squares + i**2

cubes = cubes + i**3

return(squares, cubes)

sumOfSquares Function

def sumOfSquares(N):

squares = 0

for i in range(1, N+1):

squares = squares + i**2

return squares

sumOfCubes Function

def sumOfCubes(N):

cubes = 0

for i in range(1, N+1):

cubes = cubes + i**3

return cubes

Explanation:

Explaining the addUpSquaresAndCubes Function

This line defines the function

def addUpSquaresAndCubes(N):

The next two lines initializes squares and cubes to 0

squares = 0

cubes = 0

The following iteration adds up the squares and cubes from 1 to user input

for i in range(1, N+1):

squares = squares + i**2

cubes = cubes + i**3

This line returns the calculated squares and cubes

return(squares, cubes)

<em>The functions sumOfSquares and sumOfCubes are extract of the addUpSquaresAndCubes.</em>

<em>Hence, the same explanation (above) applies to both functions</em>

7 0

3 years ago

Write a function string middle(string str) that returns a string containing the middle character in str if the length of str is

Katen [24]

Answer:

function getMiddle(s) {

return s.length % 2 ? s.substr(s.length / 2, 1) : s.substr((s.length / 2) - 1, 2);

}

// I/O stuff

document.getElementById("submit").addEventListener("click", function() {

input = document.getElementById("input").value;

document.getElementById("output").innerHTML = getMiddle(input);

});

Explanation:

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

6 0

3 years ago