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Gnoma [55]
3 years ago
5

Evaluate the following: 6+ (5 + 1).

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:12

Step-by-step explanation:6+(5+1)

5+1=6

6+(6)=12

Vsevolod [243]3 years ago
3 0
6+(5+1)
(5+1)=6
6(6)
6x6= 36
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Median is 6 range is 9 mode is 6 and mean is 7
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2 years ago
Divide (15x^2+x-8)/(3x-1)
blondinia [14]
<span>Simplifying -15x2 + -2x + 8 = 0
 Reorder the terms: 8 + -2x + -15x2 = 0 Solving 8 + -2x + -15x2 = 0 Solving for variable 'x'.
 Factor a trinomial. (2 + -3x)(4 + 5x) = 0 Subproblem 1Set the factor '(2 + -3x)' equal to zero and attempt to solve:
 Simplifying 2 + -3x = 0 Solving 2 + -3x = 0
 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3x = 0 + -2
 Combine like terms: 2 + -2 = 0 0 + -3x = 0 + -2 -3x = 0 + -2
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 Divide each side by '-3'. x = 0.6666666667
 Simplifying x = 0.6666666667
Subproblem 2
Set the factor '(4 + 5x)' equal to zero and attempt to solve:
 Simplifying 4 + 5x = 0
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Solutionx = {0.6666666667, -0.8}</span>
4 0
3 years ago
On a recent quiz, the class mean was 72 with a standard deviation of 4.2. Calculate the z-score (to 2 decimal places) for a pers
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Answer:

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Step-by-step explanation:

The standard normal deviate (Z) for a normal distribution is given by

Z=\frac{X-\bar{X}}{\sigma }

where,

X = the value of observation

\bar{X} is mean of the observations and

σ = standard deviation of the score

Applying values we get

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3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

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So we have

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The last expression has a more compact form in terms of the so-called multinomial coefficient,

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2 years ago
Please help im really confused :(​
pantera1 [17]

Answer:

a) π

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Step-by-step explanation:

C = πd

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2) plug in approximate value of 3.14 for π: 105 = (3.14) d

3) isolate to solve for d: 105/3.14 = d

4) simplify: 105/3.14 ≈ 33.4

5 0
3 years ago
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