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Gnoma [55]
3 years ago
5

Evaluate the following: 6+ (5 + 1).

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:12

Step-by-step explanation:6+(5+1)

5+1=6

6+(6)=12

Vsevolod [243]3 years ago
3 0
6+(5+1)
(5+1)=6
6(6)
6x6= 36
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Kaylen earned $14.87 selling cookies and $7.76 selling
tatuchka [14]
Kaylen has $12.63 left.

$14.87 + $7.76 = $22.63
$22.63 - $10.00 = $12.63
4 0
3 years ago
Ben is paid £8.50 per hour.
skelet666 [1.2K]

Answer:

£103.70

Step-by-step explanation:

Payment per hour = £8.50

Overtime payment = 1.4 × 8.50

= £11.90

Ben worked for 11 hours.

Normal time = 8 hours

Overtime = 3 hours

Total earnings = (8 hours × 8.50) + (3 hours × 11.90)

= £68 + £35.7

= £103.70

Ben earned £103.70 for working for 11 hours

3 0
3 years ago
g natasha is in a class of 30 students that selects 4 leaders. How many ways are there to select the 4 leaders so that natasha i
Papessa [141]

Answer:

<h2>3,654 different ways.</h2>

Step-by-step explanation:

If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).

Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.

29C3 = 29!/(29-3)!3!

29C3 = 29!/(26!)!3!

29C3 = 29*28*27*26!/26!3*2

29C3 = 29*28*27/6

29C3 = 3,654 different ways.

This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders

5 0
2 years ago
A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud
iris [78.8K]

Answer:

-0.048

Do not reject  H_0:P_1-P_2=0

Step-by-step explanation:

From the question we are told that

Sample size n_1=350

Sample size n_2=250

Sample proportion 1  \hat P= \frac{25}{350} =>0.07

Sample proportion 2 \hat P= \frac{19}{250} =>0.076

95% confidence interval

Generally for 95% confidence level

Level of significance

 \alpha = 1-0.95=>0.05

 \alpha /2=\frac{0.05}{2} =>0.025

Therefore

Z_a_/_2=1.96

Generally the equation for confidence interval between P_1 - P_2  is mathematically given as

(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2}  }

(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250}  }

(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4  }

(-0.006)\pm 0.042

(-0.006)- 0.042=>-0.048

(-0.006)+ 0.042=>0.036

Therefore

Confidence interval is

-0.048

Conclusion

Given the confidence interval has zero

Therefore do not reject  H_0:P_1-P_2=0

6 0
2 years ago
During the holiday sale, Deal of the Day sold radios and sweaters in the ratio 5:8. The store sold a total of 26 items. How many
poizon [28]

let's common be "x" 8x add 5x equal to 13 x now x equal to 26 devise 13 equal to 2,. so ans is 2

6 0
2 years ago
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