Answer:
0.28cm/min
Step-by-step explanation:
Given the horizontal trough whose ends are isosceles trapezoid
Volume of the Trough =Base Area X Height
=Area of the Trapezoid X Height of the Trough (H)
The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)
The Volume of water in the trough at any time
=8h(8+2x)
V=64h+16hx
We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles
x/h=1/4
4x=h
x=h/4
Substituting x=h/4 into the Volume, V
h=3m,
dV/dt=25cm/min=0.25 m/min
=0.002841m/min =0.28cm/min
The rate is the water being drawn from the trough is 0.28cm/min.
Answer: I'm assuming you want to know how much surface area his fence is, so 40
Step-by-step explanation: First we can divide 15 by 3 to get 5, and then multiply 5 by 8. This gives us 40, which is our answer.
Hope this helps :)
Answer:
V(t) = 2500(0.86)^t where t = the year.
Step-by-step explanation:
Each year the value will be 100 - 14 = 86% ( - 0.86) of the previous year.
Answer:
y= 0.75x + -0.50
A or B is what im guessing
<span>Find the square root of 2 between 1.3 and 1.4
=> Square root of 2 is 1.4
Square root is a number that is multiplied twice like x2, y2
=> 1.4 is the square root of 2
Now, let’s check if we got the correct answer:
=> 1.4 * 1.4
=> 1.96 or rounded to 2
Notice that the square root of 2 is a decimal number, this is called not perfect squares.
Perfect square root are those with whole numbers answers.
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