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andreev551 [17]
3 years ago
10

A merchant can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment, he sent a total of 96 boxes. I

f there are more large boxes than small boxes, how many cartons did he ship?
Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0
To figure this out, you should think about the multiples of 10 boxes you could have.

If I had 10 small boxes, there would need to be 86 large boxes. 86 is not evenly divisible by 8 so that doesn't work.

If I had 20 small boxes, there would be 76 large boxes. 76 is not evenly divisible by 8.

If I had 30 small boxes, there would be 66 large boxes. 66 is not evenly divisible by 8.

If I had 40 small boxes, there would be 56 large boxes. 56 is every divisible by 8.

4 cartons of 10 small boxes and 7 cartons of 8 large boxes would be needed. This is a total of 11 cartons.
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24x² + 14x - 5 i need all the steps
postnew [5]

Answer:

(6x+5)(4x−1)

Step-by-step explanation:

24x² + 14x - 5        Factor the expression

(6x+5)(4x−1)           Double check the answer by FOILing

24x² - 6x + 20x - 5    Combine like terms

24x² + 14x - 5            This answer does work

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3 years ago
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Answer each question below.<br> 18.<br> (16)<br> ZW and ZY are supplementary. If m
lianna [129]

Is there anymore words?

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2 years ago
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Write an equation in slope-Intercept form for the line with slope 2 and y-Intercept - 1. Then graph the line.
Yakvenalex [24]

Answer:

Solution given in the photo

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2 years ago
Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for V
ryzh [129]

Answer:

a.

∑x=109, ∑x²=4173, ∑y=87, ∑y²=2083.

b.

sample mean for x=10.9.

variance for x=331.66.

standard  deviation for x=18.21.

sample mean for y=8.7.

variance for y=147.34.

standard  deviation for y=12.14.

c.

75% Chebyshev interval around the mean for x values

-25.52,47.32

75% Chebyshev interval around the mean for y values

-15.58,32.98

The interval shows that Vanguard Balanced index has smaller spread.

d.

coefficient of variation for x=167.06%

coefficient of variation for y=139.54%

Smaller CV means lower risk so, smaller CV is better.

Step-by-step explanation:

Note: ALL ANSWERS ARE ROUNDED TO TWO DECIMAL PLACES

a.

∑x=17+0+17+28+28+27+29−12−12−13=109,

∑x²=17²+0²+17²+28²+28²+27²+29²+(−12)²+(−12)²+(−13)²=4173,

∑y=14−2+27+18+20+11+14−2−3−10=87,

∑y²=14²+(−2)²+(27)²+(18)²+(20)²+(11)²+(14)²(−2)²+(−3)²+(−10)²=2083.

b.

sample mean for x=∑x/n=109/10=10.9.

variance x=\frac{sum(x-mean )^2}{n-1}

x-mean

6.10

-10.90

6.10

17.10

17.10

16.10

18.10

-22.90

-22.90

-23.90

sum(x-mean)²=6.10 ²+(-10.90 )²+6.10 ²+17.10² +17.10²+ 16.10² +18.10² +(-22.90 )²+(-22.90 )²+(-23.90 )²=2984.9

variance  x=\frac{2984.9}{9}

Variance for x=331.66.

standard  deviation for x=√variance for x

standard  deviation for x=√331.66

standard  deviation for x=18.21.

sample mean for y=∑y/n=87/10=8.7.

variance y=\frac{sum(y-mean )^2}{n-1}

y-mean

5.30

-10.70

18.30

9.30

11.30

2.30

5.30

-10.70

-11.70

-18.70

sum(y-mean)²=5.30 ²+(-10.70 )²+18.30² +9.30² +11.30² +2.30² +5.30² +(-10.70 )²+(-11.70 )²+(-18.70 )²=1326.1

variance  y=\frac{1326.1}{9}

variance for y=147.34.

standard  deviation for y=√variance for y

standard  deviation for y=√147.34

standard  deviation for y=12.14.

c.

75% Chebyshev Interval

mean±k standard deviation

We have to find value of k.

1-\frac{1}{k^{2} } =0.75

1-0.75 =\frac{1}{k^{2} }

\frac{1}{k^{2} }=0.25

k²=4

k=2

so, 75% Chebyshev Interval for x

10.9±2*(18.21)

[-25.52,47.32]

75% Chebyshev Interval for y

8.7±2*(12.14)

[-15.58,32.98]

The interval shows that Vanguard Balanced index has smaller spread.

d.

CV for x=\frac{S.Dx}{meanx} *100

CV for x=\frac{18.21}{10.9} *100

CV for x=167.06%

CV for y

CV for y=\frac{S.Dy}{meany} *100

CV for y=\frac{12.14}{8.7} *100

Cv for y=139.54%

The smaller CV shows the smaller amount of risk so, smaller CV is better.

4 0
3 years ago
How to expand 6x(x-2y)
arlik [135]

Answer:

6x^{2} - 12xy

Step-by-step explanation:

6x  × x = 6x^{2}

6x  ×  -2y = -12xy

6x^{2} - 12xy

3 0
2 years ago
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