Any applicent that went for 3-5, 6-8, or 9-11 went to fewer than 12 interviews. Therefore, we need to total these three columns up to find all the applicents that went on fewer than 12. 3-5 went on 6, 6-8 went on 8, and 9-11 went on 5. Therefore, 6 + 8 + 5 = 19 applicents.
Step-by-step explanation:
35. 1000 m / 1 km = 10³
Move the decimal point 3 places to the right.
36. 100 cm / 1 m = 10²
Move the decimal point 2 places to the right.
37. 1 mm / 1000 μm = 10⁻³
Move the decimal point 3 places to the left.
38. 1 km / 1000 m × 1 m / 100 cm = 10⁻⁵
Move the decimal point 5 places to the left.
39. 1 Mm / 10⁶ m × 1 m / 10⁶ μm = 10⁻¹²
Move the decimal point 12 places to the left.
40. 100 cm / m × 1000 m / km = 10⁵
Move the decimal point 5 places to the right.
Answer:
m = -1/3
Step-by-step explanation:
The slope of the line can be calculated using the slope formula.
Since this is the line with points AB, the slope of any line perpendicular to it will be -1/3. All perpendicular lines cross at a 90 degree angle and as such their slopes are the negative reciprocals of each other. This means 3 becomes -1/3.
Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
Answer:
140
Step-by-step explanation:
First we would find the unit rate of students per seventh. So we would do 40 divided by 2 which gives us 20. So per 1/7 we have 20 students. Which we can then say 7 x 20 = 140. So in total there are 140 students
Hope this helped
