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3 years ago

14

In a golf tournament, players competed in pairs. Joey and Melissa were partners. Joey got a score of +8, and Melissa got a score

of -4. What was their combined score?

1 answer:

lisabon 2012 [21]3 years ago

3 0

Answer:

4

Step-by-step explanation:

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Pls answer! Dylan spots an airplane on radar that is currently approaching in a straight line, and

anastassius [24]

Answer:

13510 ft

Step-by-step explanation:

I have attached a triangle diagram to depict this situation.

From the diagram, we see that distance between A and B is denoted by x.

Now, from trigonometric ratios in this type of triangle, let's first find y.

6400/y = tan 36

y = 6400/tan 36

y = 8808.84 ft

Now, we can find x from;

6400/(8808.84 + x) = tan 16

6400/tan 16 = 8808.84 + x

22319.452 = 8808.84 + x

x = 22319.452 - 8808.84

x ≈ 13510 ft

5 0

3 years ago

Whats the value of x?

Nutka1998 [239]

Answer:

x = 8 units, measure of angle AFE = 60 degrees, measure of angle CFD = 60 degrees

Step-by-step explanation:

Finding x:

You know all three of the given measures add up to 180 because they are on the same side of the line. Write an equation and solve for x.

6x + 2 + 8x + 6 + 7x + 4 = 180

21x = 168 --> x = 8

Angle AFE:

Substitute the value of x in the given measure.

7x + 4 = 7*8 + 4 = 56 + 4 = 60

Measure of angle CFD:

Angle AFE is it's vertical angle, so their measures (60 degrees) are equal.

7 0

3 years ago

NEED HELP ASAP What is true about the points on the graph of Y=3^x?

galben [10]

Answer:

d

Step-by-step explanation:

The answe of this question is d

3 0

3 years ago

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago

George and Chin work as landscapers. George charges $90 for a 6-hour job. Chin charges $84 for the same job.The table shows thei

gulaghasi [49]

The equation must equal 84, so you can eliminate B and D.

Chin charges a rate for 2 hours, then charges a reduced rate for 4 hours. There are no discounts present in his rate, so you can eliminate A.

The equation for Chin's charges can be found by the equation C. 2x + 4y = 84.

7 0

3 years ago

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