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3 years ago

A set of data is described in the following box-and-whisker plot. The ____ of this set is 8.

Mathematics

2 answers:

monitta3 years ago

6 0

Range: the maximum is 11 and the minimum is 3. Range is the max minus the min, so 11-3=8.

xeze [42]3 years ago

6 0

Answer:

The correct answer is Range.

Step-by-step explanation:

For box-and-whisker plot, the range is illustrated by the distance between the opposite ends of the whiskers, you ignoring the outliers.

In this case, the whisker starts at 3 and ends at 11.

Range = 11-3 = 8.

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Is the following relation a function? Give the domain and range

Angelina_Jolie [31]

That relaton i a function

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3 years ago

Help me with this please!!

valina [46]

<h2><u>Given:</u><u>-</u></h2>

Points C = (-7,2) → $\sf{(X_1,Y_1)}$
D = (3,12) → $\sf{(X_2,Y_2)}$

The Midpoint of CD.

<h2><u>Required</u><u> </u><u>Response</u><u>:</u><u>-</u></h2>

Let,

Midpoint of CD be (x,y).

WKT,

$\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}$

$→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}$

$→\;{\sf{\frac{-4}{2},\frac{14}{2}}}$

$→\;{\sf{-2,7}}$

The Midpoint of CD ◕➜ $\Large{\red{\mathfrak{(-2,7)}}}$

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) → $\sf{(X_1,Y_1)}$

O = (-2,7) → $\sf{(X_2,Y_2)}$

$\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}$

$→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}$

$→\;{\sf{\sqrt{5²+5²}}}$

$→\;{\sf{\sqrt{25+25}}}$

$→\;{\sf{\sqrt{50}}}$

$→\;{\sf{5√2 (or) 7.07}}$

Radius of Circle ◕➜ $\Large{\red{\mathfrak{7.07}}}$

<h2>Option D.</h2>

Hope It Helps You ✌️

3 0

3 years ago

A magician is performing for an audience of 32 men and 20 women. He selects a volunteer from the audience, has the volunteer sta

g100num [7]

The correct answer is A) 37.4%.

The probability that the first volunteer is a man would be 32/52, since there are 32 men out of 52 people. The probability that the second volunteer would also be a man would be 31/51, since there is 1 fewer man and 1 fewer person total to choose from.

32/51(31/51) = 992/2652 = 0.374 = 37.4%.

8 0

3 years ago

Solve.<br> -2(3x + 7) = -8x

tia_tia [17]

Answer:

x=7

Step-by-step explanation:

-6x-14=-8x

-6x+8x=14

2x=14

x=7

4 0

2 years ago

Read 2 more answers

A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round you

prisoha [69]

The volume of the prop is calculated to be 1,875.6 cubic inches.

Step-by-step explanation:

Step 1:

The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying $\frac{1}{3}$ with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 8 inches and the height is 12 inches.

The volume of the cone: $\frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.14) (8^{2}) (12)= 803.84$ cubic inches.

Step 3:

The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying $\frac{4}{3}$ with π and the cube of the radius (r³).

Here the radius is 8 inches. We take π as 3.14.

The volume of a full sphere $= \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.14) (8^{3} ) = 2,143.573$ cubic inches.

The volume of the half-sphere $= \frac{2,143.573}{2} = 1,071.7865$ cubic inches.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume = $803.84+1,071.7865 = 1,875.6265$ cubic inches.

Rounding this off, we get the volume of the prop as 1,875.6 cubic inches.

6 0

3 years ago