Answer:
The value of Mary's investment after two years = £12362.7
Step-by-step explanation:
P = Principal / initial amount
R = rate of interest per cent per year
T = number of years
A = final amount at the end of T years
Then:
A = P*(1 + R/100)^2
In our example:
P = £12000
R = 1.5 per cent per year
T = 2 years
Thus:
A = 12000*(1 + 1.5/100)^2
= 12000*(1 + 0.015)^2
= 12000*(1.015)^2
= 12000*(1.030225)
= 12362.7
Value of investment after two years = £12362.7
Answer: x=9
Step-by-step explanation:
7x+43=106
subtract 43 from both sides
7x=63
divide by 7
x=9
The answer should be $29,952.... I hope this helps
For this case, the first thing we want to do is substitute the value of y = 15 in the equation.
We have then:
15 = -0.08x ^ 2 + 1.6x + 10
Rewriting we have:
0 = -0.08x ^ 2 + 1.6x + 10 - 15
0 = -0.08x ^ 2 + 1.6x - 5
The solutions are:
x1 = 3.876275643042054
x2 = 16.123724356957947
Nearest whole number:
x1 = 4
x2 = 16
were about 15 tons of trout caught in the lake in the years:
1995 + 4 = 1999
1995 + 16 = 2011
Answer:
The year 1999 and the year 2011
Answer: 2 per month
8 per four months
Step-by-step explanation:
