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ivann1987 [24]
3 years ago
12

What is the area of the base of the cone below? Round the answer to the nearest tenth if necessary. A cone with height 8 inches

and volume 52 inches cubed. 14.7 inches squared 17.3 inches squared 18.5 inches squared 19.5 inches squared
Mathematics
2 answers:
docker41 [41]3 years ago
7 0

Answer:

The area of the circle is 19.5 in²

Step-by-step explanation:

First of all to solve this problem we have to know the formula to calculate the volume of a cone

v = volume  = 52 in³

r = radius

h = height  = 8 in

π = 3.14

v = 1/3 * π * r² * h

we solve r

3 * v /h * π = r²

we replace the known values

3 * 52 in³ / 3.14 * 8 in = r²

156 in³ / 25.12 in = r²

6.21 in² = r²

√6.21 in² = r

2.49 in = r

now that we have the radius we need to use the area formula of a circle:

a = area

r = radius = 2.49 in

π = 3.14

a = π * r²

we replace the known values

a = 3.14 * (2.49 in)²

a = 3.14 * 6.21 in²

a = 19.5 in²

The area of the circle is 19.5 in²

denpristay [2]3 years ago
7 0

Answer:

19.5

Step-by-step explanation:

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What is a cube number that us greater than 100 but less that 200
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3 years ago
True or false: Every sequence is either arithmetic or geometric. If this is true, explain. If false,
tiny-mole [99]

In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number r such that

a_{n+1}-a_n=r\quad \forall n\geq 1

In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number r such that

\dfrac{a_{n+1}}{a_n}=r\quad \forall n\geq 1

So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.

For example, any sequence starting with

1, 15, -3,\ldots

Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.

5 0
3 years ago
[ANSWER FOR BRAINIEST]
s2008m [1.1K]

Note the order of the letters:

A C E G

M N P R

You read it like this:

A ≅ M

C ≅ N

CE ≅ NP

AG ≅ MR

... and so on

In the following choices:

CE ≅ NP is the true statement

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nevsk [136]

Answer:

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Step-by-step explanation:

Let f(x)=x^3+x+7

So f'(x)=3x^2+1

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

Let x_1=-2

We are going to find x_2

So we are evaluating -2-\frac{f(-2)}{f'(-2)}

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

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So

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5 0
2 years ago
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